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melamori03 [73]
3 years ago
6

Can someone pls tell me the answers to all of these??

Mathematics
2 answers:
choli [55]3 years ago
7 0
A) x= 34
b) x= 87
C) x= 17
Llana [10]3 years ago
6 0

Answer:

Left up x=34

Left down x=87

Right x=17

Step-by-step explanation:

The picture is the working out.

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Help me please answer thanks
attashe74 [19]

Answer:

I think it would be each girl scored 2 points, and each boy only scored one. :)

3 0
3 years ago
How is everyonesss dayyy- is anyone else on spring break?
Harlamova29_29 [7]

Answer:

my day is good so far......I will be going on spring break but I would still have a lot of school work to do so I dont know if I'll enjoy it:(((((((

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5 0
3 years ago
Read 2 more answers
What is the product?
Kazeer [188]

Answer:

2) -81t² +16

Step-by-step explanation:

(9t -4)(-9t -4) = (9t x -9t) + (9t x -4) + (-4 x -9t) + (-4 x -4)

                     = -81t² - 36t + 36t + 16

                     = -81t² + 16

4 0
2 years ago
Read 2 more answers
Marc mixes blue and yellow paint to make his favorite shade of green, which he'll use to paint his house. He has 14 cans of blue
Murljashka [212]

Answer: 1. 7:10

2. 10 blue cans

15 yellow cans.

3. 4 cans of blue paint.

5 cans of yellow paint.

4. 2 blue cans and 3 yellow cans.

Step-by-step explanation:

1. 14 blue paint cans/20 yellow paint cans=

14/20=

7/10 ==> 7:10

2. 4+6 blue cans=10 blue cans

6+9 yellow cans=15 yellow cans.

3. 14-10=4 cans of blue paint.

20-15=5 cans of yellow paint.

4. 10 blue cans/15 yellow cans=

10/15=

2/3 ==> 2:3 ==> 2 blue cans and 3 yellow cans.

5 0
9 months ago
Read 2 more answers
Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,
Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}

4 0
2 years ago
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