Answer:
wish i could friend, wish i could
Explanation:
sorry, have a good day and life lol
biotic- living things
abiotic- non living things
Answer:
Up-regulation.
Explanation:
Hormones may be defined as the chemical messengers of the body that can transmit information and maintains homeostasis. The hormones can directly go into the bloodstream and may release through the special ducts.
The receptors of the hormone is required for the binding of the receptors. To maintain the normal homeostasis of the body, the body shows the up regulation and down regulation. In up regulation the hormone levels increases in the body by increasing the receptor on the specific target organ.
Thus, the correct answer is up regulation.
The answer is C.
The man’s genotype must be AB. The woman’s genotype can be either BB or BO as both correspond to a blood type (which is a phenotype) of B.
Each parent passes on one allele. The man can contribute A or B and the woman can contribute B or O.
The possible genotype combinations are therefore AB, AO, BB, and BO. These correspond to the phenotypes AB, A, B, and B.
Complete question:
Suppose "A" is a dominant gene for the ability to taste phenylthiocarbamide and "a" is a recessive gene for the inability to taste it. Which couples could possibly have both a child who tastes it and a child who does not?
a. father AA, mother aa
b. father Aa, mother AA
c. father Aa, mother Aa
d. father AA, mother AA
Answer:
c. father Aa, mother Aa
Explanation:
According to the given information, the ability to taste phenylthiocarbamide is a dominant trait and is imparted by the allele "A". This phenotype would be expressed in both homozygous and heterozygous conditions. The non-taster phenotype would be expressed in the homozygous recessive genotypes only.
To have both taster and non-taster children, both the parents should have at least one copy of the recessive allele. Among the given options, the father with genotype Aa and the mother with genotype Aa have the possibility to have both taster and non-taster children.
Aa x Aa= 3/4 taster (1/4 AA and 1/2 Aa): 1/4 non-taster (1/4 aa)