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2 years ago

A line that includes the point (7, 10) has a slope of 2. what is the equation in slope-intercept

Mathematics

1 answer:

Damm [24]2 years ago

5 0

Answer:

y=2x-4

Step-by-step explanation:

y-y1=m(x-x1)

y-10=2(x-7)

y-10=2x-14

y=2x-14+10

y=2x-4

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What ia the angle of AOC and DOE

natulia [17]

(i) Angle AOC would equal 48°, as it is vertically opposite to angle DOB and they are therefore equal.

(ii) Angle DOE would equal 42°. We can see this because angles on a straight line add up to 180°, and 90 + 48 = 138, so we can do 180 - 138 = 42°.

I hope this helps!

4 0

3 years ago

If m< BOE = 130 degrees and m< cob = 80 degrees

hjlf

Answer:

then what?

Step-by-step explanation:

do we have to find the angle?

all I know is every right triangle is equal to 90°

6 0

3 years ago

Sal bought x shares of a stock that sold for 31.50 per share. He paid a 1% commission on the sale. The total cost of his investm

Licemer1 [7]

Answer:

180

Step-by-step explanation:

add 1% to 31.50 to get 31.815

then take the total 5276.70 and divide by 31.815

5 0

2 years ago

Toillet paper is sold in cases for 36 rolls for $14.99 what is the per price per roll?

Eva8 [605]

Alright, so the unknown value here we want to know is the price of one roll of TP. Let's call it "x".
36x=14.99
Divide both sides by 36 to get the price of a single roll.
x=.41638888....
We have to round this to hundredths because we're talking in cents, so...
x=.42
Each roll of toilet paper costs 42 cents.

8 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

A line that includes the point (7, 10) has a slope of 2. what is the equation in slope-intercept​

A line that includes the point (7, 10) has a slope of 2. what is the equation in slope-intercept