Question

A 2 kg watermelon is dropped from a roof and has a speed of 5 m/s just before it hits the ground. How much kinetic energy does the watermelon have at this moment?

Answer 1

Answer:

25J

Explanation:

Given parameters:

Mass of the watermelon  = 2kg

Speed before touching the ground  = 5m/s

Unknown:

Kinetic energy  = ?

Solution:

To solve this problem, we must understand that kinetic energy is the energy possessed by a body in motion.

    K.E  = $\frac{1}{2}$  m v²

m is the mass

v is the velocity

Now, insert the parameters and solve;

      K.E  =  $\frac{1}{2}$  x 2  x  5² = 25J