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pickupchik [31]

3 years ago

10

A 2 kg watermelon is dropped from a roof and has a speed of 5 m/s just before it hits the ground. How much kinetic energy does t

he watermelon have at this moment?

1 answer:

Mashcka [7]3 years ago

7 0

Answer:

25J

Explanation:

Given parameters:

Mass of the watermelon = 2kg

Speed before touching the ground = 5m/s

Unknown:

Kinetic energy = ?

Solution:

To solve this problem, we must understand that kinetic energy is the energy possessed by a body in motion.

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

Now, insert the parameters and solve;

K.E = $\frac{1}{2}$ x 2 x 5² = 25J

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After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T

Ugo [173]

Answer:

the distance is 315.3696 m

Explanation:

The computation of the distance is given below:

Given that

Sound intensity = 1.67 × 10^-6 W/m^2

And, the distance = 233 m

Now as we know that

Power = Intensity × surface area

1.67 × 10^-6 × 4π(233)^2 = 1.67 × 10^-6 ÷ 2× 4π × d^2

d^2 = 2 × (223)^2

= √2 × 223

= 315.3696 m

Hence, the distance is 315.3696 m

5 0

3 years ago

A 13500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the

Mekhanik [1.2K]

Answer

given,

mass of the jet airplane = 13500 kg

Force on the plane = 35700 N due north

force from wind = 15300 N in direction 80.0° south of west.

Force = $35700 \vec{j} N$

force by wind = $15300(-cos \theta \vec{i}-sin \theta \vec{j})$ N

= $15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$ N

net force on the jet airplane(ma)

$m a = 35700 \vec{j} + 15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$

$\vec{a} = \dfrac{35700}{13500} \vec{j} + \dfrac{15300}{13500}(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$

$\vec{a} = 2.64\vec{j} -0.197 \vec{i} - 1.116 sin 80^0 \vec{j})$

$\vec{a} = -0.197 \vec{i} + 1.524 \vec{j}$

$a = \sqrt{-0.197^2+1.524^2}$

a = 1.54 m/s²

$\theta = tan^{-1}(\dfrac{-1.524}{0.197})$

$\theta = -82.63^0$

3 0

3 years ago

When a person is standing upright, the weight of anything being lifted and carried in the hands is first reflected onto the:

hichkok12 [17]

Pelvic girdle

In human anatomy, the pelvis is a complex of bones that connects the trunk and the legs, supports and balances the trunk, and houses and supports the intestines, the urinary bladder, and the internal organ. It is sometimes referred to as the bony pelvis or the pelvic girdle.
One is located on the left side of the body and the other is located on the right. They come together to make the pelvic girdle, a portion of the pelvis. The hip bones are attached to the upper portion of the skeleton at the sacrum.
The pelvic girdle's main function is to support the upper body's weight while seated and transfer that weight to the lower limbs while standing. For the muscles in the trunk and lower limbs, it functions as attachment point.

To learn more about pelvic girdles please visit -
brainly.com/question/24394348

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8 0

2 years ago

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.10 m/s

yarga [219]

Answer:

$I=336.6kgm/s$

Explanation:

The equation for the linear impulse is as follows:

$I=F\Delta t$

where $I$ is impulse, $F$ is the force, and $\Delta t$ is the change in time.

The force, according to Newton's second law:

$F=ma$

and since $a=\frac{v_{f}-v_{i}}{\Delta t}$

the force will be:

$F=m(\frac{v_{f}-v_{i}}{\Delta t})$

replacing in the equation for impulse:

$I=m(\frac{v_{f}-v_{i}}{\Delta t})(\Delta t)$

we see that $\Delta t$ is canceled, so

$I=m(v_{f}-v_{i})$

And according to the problem $v_{i}=0m/s$ , $v_{f}=5.10m/s$ and the mass of the passenger is $m=66kg$ . Thus:

$I=(66kg)(5.10m/s-0m/s)$

$I=(66kg)(5.10m/s)$

$I=336.6kgm/s$

the magnitude of the linear impulse experienced the passenger is $336.6kgm/s$

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3 years ago

At one instant, point P is 7.30 to the left of a proton that is moving at 3.10 km/s in vacuum. The point and velocity vector lie

o-na [289]

Answer:

the unit vector points from the point charge toward where the field is measured(from proton to point P)

Explanation:

8 0

3 years ago