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masha68 [24]
3 years ago
12

A skier of mass 103 kg comes down a slopeof constant angle 32◦with the horizontal.What is the force on the skier parallel tothe

slope? Neglect friction. The accelerationof gravity is 9.8 m/s2.Answer in units of N.
Physics
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

534.9 N

Explanation:

The skier weight is his mass times gravitational acceleration g

W = mg = 103 * 9.8 = 1009.4 N

This weight can be divided into 2 components, one perpendicular and the other parallel to the 32-degree slope. The parallel component would equal to

Wsin(32^0) = 1009.4sin(32^0) = 534.9 N

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