The concentration (in M) of hydroxide ions in a solution at 25°C with a pOH of 3.58 is 2.6 × 10⁻⁴ M.
pOH is the measure of basic nature of a solution by evaluating the [OH⁻] concentration.
It is the negative logarithm of the hydroxide ion concentration.
Given,
pOH = 3.58
Temperature = 25°C = 298K
At 25°C, the relation of pOH and [OH⁻] concentration is as follows:
∴ pOH = -log [OH⁻]
⇒ 3.58 = -log [OH⁻]
⇒log [OH⁻] = -3.58
⇒ [OH⁻] = antilog (-3.58)
⇒[OH⁻] = 2.6 × 10⁻⁴ M
The concentration (in m) of hydroxide ions in a solution at 25.0 °C with a pOH of 3. 58 is 2.6 × 10⁻⁴ M.
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Answer:
the answer should be henry's law
Answer:
left
Explanation:
increase in n2 will increase the production of ammonia so it shift to the left
x=1
Simplify both sides of the equation and then isolate the variable
