Answer:
80.7 L
Step-by-step explanation:
This looks like a case where we can use the Ideal Gas Law to calculate the volume.
pV = nRT Divide both sides by p
V = (nRT)/p
=====
Data:
n = 5.00 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = (120 +273.15) K = 393.15K
p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm
=====
Calculation:
V = (5.00 × 0.082 06 × 393.15)/2.00
V = 161.3/2.00
V = 80.7 L
<span>the rapid expansion of matter from a state of extremely high density and temperature that according to current cosmological theories marked the origin of the universe.</span>
Answer:
The answer to your question is 3 moles of AlCl₃
Explanation:
Process
1.- Write and balance the equation
Al(NO₃)₃ + 3NaCl ⇒ 3NaNO₃ + AlCl₃
2.- Determine the limiting reactant
Theoretical proportion 1 mol Al(NO₃)₃ : 3 moles of NaCl
Experimental proportion 4 moles Al(NO₃)₃ : 9 moles NaCl
From these values, we determine that the limiting reactant is NaCl because the number of moles increases three times and the number of moles of Al(NO₃)₃ increases four times.
3.- Determine the amount of AlCl₃ using proportions
3 moles of NaCl --------------- 1 mol of AlCl₃
9 moles of NaCl ---------------- x
x = (9 x 1) / 3
x = 9 /3
x = 3 moles
Explanation:
Given problem:
Find the molar mass of:
SO₃ and C₁₀H₈
Solution:
The molar mass of a compound is the mass in grams of one mole of the substance.
To solve this, we are going to add the individual atomic masses of the elements in the compound;
Atomic mass;
S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol
For SO₃;
= 32 + 3(16)
= 32 + 48
= 80g/mol
For C₁₀H₈
= 10(12) + 8(1)
= 120 + 8
= 128g/mol
Answer:
The boiling point wouldn´t be effected. The amount of time it would take to get it to that point would increase
Explanation:
