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taurus [48]
2 years ago
11

55% of ADM students like salad

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
7 0

Answer:

what is the question

Step-by-step explanation:

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The ratio of the heights of two similar pyramids is 3:2. The volume of the larger pyramid is 135 cm3. What is the volume of the
gladu [14]
l-larger\\s-smaller\\\\\dfrac{h_l}{h_s}=\dfrac{3}{2}\to\dfrac{V_l}{V_s}=\left(\dfrac{3}{2}\right)^3\\\\V_l=135\ cm^3.\\subtitute\\\\\dfrac{135}{V_s}=\dfrac{27}{8}\ \ \ \ |cross\ multiply\\\\27V_s=135\cdot8\\\\27V_s=1080\ \ \ |divide\ both\ sides\ by\ 27\\\\\boxed{V_s=40\ (cm^3)}
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3 years ago
What is the image of (6,-2) under the translation (x,y) (x-5,y-8)
german
The new point would then be at (1, -10)
6 0
3 years ago
Please I need the correct answer please
Rzqust [24]

(<u>−1</u>

2  )(n^3)+

<u>1</u>

2 n^2+4.6n+(−

<u>1</u>

2)(n^3)+

<u>1</u>

2  n^2+4.5n

=

<u>−1</u>

2  n^3+

1

2  n^2+4.6n+

−1

2  n^3+

1

2  n^2+4.5n

Combine Like Terms:

=

<u>−1</u>

2  n^3+

<u>1</u>

2  n^2+4.6n+

<u>−1</u>

2  n^3+

<u>1</u>

2  n^2+4.5n

=(<u>−1</u>

  2   n^3+

<u>−1</u>

2   n^3)+(

<u>1</u>

2  n^2+

<u>1</u>

2   n^2)+(4.6n+4.5n)

=−n^3+n^2+9.1n

Answer:

=−n^3+n^2+9.1n

     Everything underlined means its a  fraction/divided hope this helps <em>:D</em>

8 0
3 years ago
If 1 sec = 5 dots how many dots will there be in 20 secs
Natali5045456 [20]
5*20=100, the answer would be 100 dots
4 0
3 years ago
Jane needs to buy mulch to cover a circular garden
scoray [572]

Answer:

$3089.4

Step-by-step explanation:

A circle is a locus of a point such that its distance from a point known as the center is always constant.

The area of a circle is given by the formula:

Area = πr²; where r is the radius of the circle.

From the image attached, we can see that the garden is circular with a radius of 5.5 yard. Hence:

Amount of mulch needed to cover garden = area of garden = πr² = π(5.5)²  = 95 yd²

Since mulch cost $32.52 per square yard, hence:

Cost of mulch needed = $32.52 per yd² * 95 yd² = $3089.4

7 0
2 years ago
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