Answer:
Option B is correct.
Reason:It is an argument
Step-by-step explanation:
Given:
and ![BC \cong EF](https://tex.z-dn.net/?f=BC%20%5Ccong%20EF)
By transitive property: a = b and b = c then, a =c
⇒![AB \cong EF](https://tex.z-dn.net/?f=AB%20%5Ccong%20EF)
AB = EF [def of
segment]
By Segment Addition Postulate states that given two points A and C, and a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation
AB + BC = AC.
Since, the line segment EG , F lies on the line segment;
then, by segment addition postulates we have;
EG = EF + FG
By substitution AB=EF
⇒ EG = AB + FG hence proved!
Since, in the fourth statement reason is: It is an argument