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PIT_PIT [208]
3 years ago
11

Which part of the proof does the fourth statement and reason represent?

Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

Option B is correct.

Reason:It is an argument

Step-by-step explanation:

Given: AB \cong BC  and BC \cong EF

By transitive property:  a = b  and b = c then, a =c

⇒AB \cong EF

AB = EF                                [def of \cong segment]

By Segment Addition Postulate states that given  two points A and C, and a third point B lies on the line segment AC if and only if the distances between the  points satisfy the equation

AB + BC = AC.

Since, the line segment EG , F lies on the line segment;

then, by segment addition postulates we have;

EG = EF + FG

By substitution AB=EF

⇒ EG = AB + FG                     hence proved!

Since, in the fourth statement reason is:  It is an argument

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A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590
Jet001 [13]

Let's assume

height of plane  in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

y-y_1=m(x-x_1)

points as

(5,6500)

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(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

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now, we can plug values

m=\frac{5900-6500}{7-5}

m=-300

Equation of line:

we can use formula

y-y_1=m(x-x_1)

we can plug values

h-6500=-300(t-5)

h=-300t+8000

Time of landing:

we can set h=0

and then we can solve for t

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5 0
3 years ago
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The line y = hx - 2 where h &gt; 0 meets the curve 3y² = 9x² - 6x + 1.
I am Lyosha [343]

Answer:

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Step-by-step explanation:

since y =hx -2 is an equation for a line which intersects with the curve 3y^2 = 9x^2 - 6x +1. The point of intersection, let's say (x_1,y_1), should satisfy the two equations. As a result, the value of y in the second equation can be replaced with the value of y in the first equation as the following,

3y^2 = 3(hx-2)^2 = 9x^2 - 6x +1\\3(h^2x^2 -4hx + 4) = 9x^2 - 6x + 1\\3h^2 x^2 -12hx +12 = 9x^2 - 6x +1

therefore, the latter equation can be rewritten in a quadratic equation form as the following,

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if the line is tangent to the curve, it means that the line touches the curve at one point, therefore the discernment of the second order equation will be equal to zero for the famous quadratic equation solution.

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where a=9-3h^2, b=12h-6 and c=-11, as a result, the following equations can be deduced,

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therefore, dividing both sides by 12

h^2 -12 +36 =0\\(h-6)^2 =0\\h=6

8 0
2 years ago
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