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Svet_ta [14]
4 years ago
5

A boat costs 19,200 and decreases in value by 12% per year. how much will the boat be worth after 5 years

Mathematics
2 answers:
AlexFokin [52]4 years ago
8 0
 it is $10,132.45 or multiply the original value by .88 five times, once for each year
olganol [36]4 years ago
8 0

Answer

Find out the how much will the boat be worth after 5 years.

To prove

As given

A boat costs $19,200 and decreases in value by 12% per year.

This is denoted by the exponential decreasing function.

y = a (1 - i)^{t}

Where y is the intial value, i is the interest in the decimal form and t is the time.

Here

a =  $19,200

t = 5 years

i = 12 %

12% is written in the decimal form

= \frac{12}{100}

= 0.12

Put in the formula

y = 19200(1 - 0.12)^{5}

y = 19200 × 0.527732

y = $10132.5 (Approx)

Therefore  the boat  worth after 5 years will be $10132.5 (Approx)


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Answer:

the answer is In the set of ordered pairs {(-2, 0), (0, 6), (2, 12), (4, 18)}, the domain is the set of the first number in every pair (those are the x-coordinates): {-2, 0, 2, 4}. The range is the set of the second number of all the pairs (those are the y-coordinates): {0, 6, 12, 18}. This table describes y as a function of x


i hope this helps u okay and can i get brainleiest

Step-by-step explanation:


4 0
4 years ago
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ArbitrLikvidat [17]

Answer:

x = -5/2

Step-by-step explanation:

4x+2 = -8

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4 0
2 years ago
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Vsevolod [243]
D- I could be wrong
6 0
3 years ago
The base of a solid is the region in the first quadrant between the graph of y=x2 and the x -axis for 0≤x≤1 . For the solid, eac
nata0808 [166]

Answer:

The volume of the solid is π/40 cubic units.

Step-by-step explanation:

Please refer to the graph below.

Recall that the area of a semi-circle is given by:

\displaystyle A=\frac{1}{2}\pi r^2

The volume of the solid will be the integral from <em>x</em> = 0 to <em>x</em> = 1 of area A. Since the diameter is given by <em>y</em>, then the radius is <em>y/2</em>. Hence, the volume of the solid is:

\displaystyle V=\int_0^1\frac{1}{2}\pi \left(\frac{y}{2}\right)^2\, dx

Substitute:

\displaystyle V=\frac{1}{2}\pi\int_0^1\left(\frac{x^2}{2}\right)^2\, dx

Simplify:

\displaystyle V=\frac{1}{2}\pi \int_0^1\frac{x^4}{4}\, dx

Integrate:

\displaystyle V=\frac{1}{2}\pi \left[\frac{x^5}{20}\Big|_0^1\right]

Evaluate:

\displaystyle V=\frac{\pi}{40}\left((1)^5-\left(0\right)^5\right)=\frac{\pi}{40}\text{ units}^3

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4 0
3 years ago
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liraira [26]

Answer:

option d is correct 3,2

4 0
4 years ago
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