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eimsori [14]
3 years ago
9

If y=15 when x=5, find y when x=7, given that y varies directly with x.

Mathematics
1 answer:
Oxana [17]3 years ago
4 0

Answer:

when x = 7, y = 21

Step-by-step explanation:

This is about direct variation. If y varies directly with x, then there is a constant  factor of variation, k. The constant of variation can be found by ʸ⁄ₓ

k = ʸ⁄ₓ

k = ¹⁵⁄₅ = 3

Now that we have found k, we simply multiply x by it to find y (this is because y is directly proportional to x). We plug in our x = 7 to find y at this point.

y = 3x

y = 3(7)

y = 21

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Step-by-step explanation:

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Simplify the expression 3s - 3s 35 - 3s =​
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Answer:

6s-35

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Eddie lange earns 11.50 per hour.he worked 40 hours plus time and a half for 7 hours.
VladimirAG [237]

Answer:

580.75

Step-by-step explanation: 11.50 * 40 =460

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6 0
3 years ago
What is the equation of a circle whose center at (-5, -2) and radius is 2?​
aliya0001 [1]

The equation of a circle whose centre (-5,-2) and radius 2 is x^{2}+y^{2}+10x+4y+25=0

What is equation of a circle?

A circle is a closed curve drawn from a fixed point called centre of the circle. The distance between the centre of the circle and the arc of the circle is called the radius of the circle.

The equation of a circle with centre (h, k) radius r is

(x-h)^{2} +(y-k)^{2}=r^{2}

Given center = (-5,-2)  and Radius = 2

Put the Given value in the equation:

= (x-(-5))^{2} +(y-(-2))^{2} = 2^{2}

= (x+5)^{2} +(y+2)^{2}=2^{2}

= (x^{2} +10x+25)+(y^{2}+4y+4)= 4

= x^{2} +y^{2}+10x+ 4y+ 29 = 4

= x^{2} +y^{2}+10x +4y+ 29-4=0

= x^{2} +y^{2}+10x+4y+25=0

So, the equation of the circle whose centre is (-5,-2) and Radius 2 is

x^{2}+y^{2}+10x+4y+25=0

To read more about the equation of a circle. you can follow:

brainly.com/question/351704

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6 0
2 years ago
Urgent, Please help!
yarga [219]

Answer:

<h2>min: 52</h2><h2>max: 78</h2><h2>median: 63</h2><h2>lower quartile median: 54</h2><h2>upper quartile median: 73</h2><h2>interquartile range: 19</h2>

Step-by-step explanation:

the temperatures ordered from least to greatest

52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78

the min is 52

the max is 78

median:

52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78

(62+64)/2=126/2=63

thus the median is 63

now we don't include the median in finding the upper and lower quartile medians:

lower quartile median:

52, 53, 54, 54, 57, 62

54 (same #s no need to add up and divide by 2)

upper quartile median:

64, 69, 73, 73, 77, 78

73 (same #s no need to add up and divide by 2)

interquartile range is:

upper quartile median-lower quartile median:

73-54

19

8 0
3 years ago
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