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1 year ago

What is the equation of a circle whose center at (-5, -2) and radius is 2?

Mathematics

1 answer:

aliya0001 [1]1 year ago

6 0

The equation of a circle whose centre ( $-5,-2$ ) and radius $2$ is $x^{2}+y^{2}+10x+4y+25=0$

What is equation of a circle?

A circle is a closed curve drawn from a fixed point called centre of the circle. The distance between the centre of the circle and the arc of the circle is called the radius of the circle.

The equation of a circle with centre $(h, k)$ radius $r$ is

$(x-h)^{2} +(y-k)^{2}=r^{2}$

Given center = $(-5,-2)$ and Radius = $2$

Put the Given value in the equation:

= $(x-(-5))^{2} +(y-(-2))^{2} = 2^{2}$

= $(x+5)^{2} +(y+2)^{2}=2^{2}$

= $(x^{2} +10x+25)+(y^{2}+4y+4)= 4$

= $x^{2} +y^{2}+10x+ 4y+ 29 = 4$

= $x^{2} +y^{2}+10x +4y+ 29-4=0$

= $x^{2} +y^{2}+10x+4y+25=0$

So, the equation of the circle whose centre is $(-5,-2)$ and Radius $2$ is

$x^{2}+y^{2}+10x+4y+25=0$

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A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable

Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

5 0

2 years ago

A group of artists is selling small prints to raise money for charity. They sell p prints, and make a profit of f(p) on the sale

liraira [26]

The correct answer is is D) If the group sells 15 prints they will loose $85.

To figure out which statement is true, we have to evaluate the function ,

$p(x)=17x-340$ for all the values given in options (A)-(D). A negative output represents a loss and a positive output will represent a profit.

In A $p=12$ so $f(12)=17\times 12-340=-136$ . In this case we gather that if they sell 12 prints, they will make a loss of $136. This tells us that option A is wrong.

In B, $p=28$ so $f(28)=17\times 28-340=136$ . In this case we gather that if they sell 28 prints, they make a profit of $136. This tells us that option B is wrong.

In C, $p=35$ so $f(35)=17\times 35-340=225$ . In this case we gather that if they sell 35 prints, they make a profit of $225. This tells us that option C is wrong.

Lastly, $p=15$ so $f(15)=17\times 15-340=-85$ . In this case we gather that if they sell 28 prints, they make a loss of 85 dollars. From this we gather that D is the correct option.