The weight in 1980 is 
kilograms
<em><u>Solution:</u></em>
From 1980 to 1990, Lior’s weight increased by 25%
His weight is "k" kilograms in 1990
<em><u>To find: weight in 1980</u></em>
This is a percentage increase problem
Let "x" be the weight in kilograms in 1980
<em><u>The percentage increase is given by formula:</u></em>
Here,
Initial value in 1980 = x
Final value in 1990 = k
Percentage increase = 25 %
<em><u>Substituting the values in formula,</u></em>
Thus the weight in kilograms in 1980 is
No because to get a proportional relationship you have to add the same number to all x to get y
Answer:
p = 23
Step-by-step explanation:
2p + 2 = 48
-2 -2
2p = 46
/2 /2
p = 23
Hope this helps and I hope u have an Amazing day!!
Answer:
see below
Step-by-step explanation:
Standard equation for a circle with center h,k and radius r
(x-h)^2 + (y-k)^2 = r^2
so for this one center = (1,2) radius = 4
<span>Let n be the number of taxis in NY. The average distance travelled is 60,000 miles, therefore the middle 95% will have the same average as the population, the reason being the mileage is symmetrically distributed about the mean Therefore the total number of miles in one year for the middle 95% is 60,000 * 0.95 * n
</span><span>The range of miles driven by the middle 95% can be found from the empirical rule that says:
For a normal distribution, approximately 95% of the data points lie within the range plus and minus 2 standard deviations of the population mean. In this case the range is
(60,000-22,000) to (60,000 + 22,000)</span>
