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Marianna [84]
2 years ago
5

Keenan got 13/25 for his mathematics test write down two equivalent fractions for this mark​

Mathematics
1 answer:
zheka24 [161]2 years ago
6 0
Answer and explanation,

You’re welcome :)

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Find the slope of the line through each pair of points.<br> (-2, -12) and (-18, -12)
Jobisdone [24]

Answer:

0/16

Step-by-step explanation:

you use the equation y2-y1/x2-x1 so -12-(-12) which is 0 then do -18-(-2)=-16 so the slope is 0/-16

4 0
3 years ago
I need a specific explanation of how to answer this
zimovet [89]
A rectangle has two dimensions, width and length, and the area of it is their product.

since we know its area is 3x²-11x-4, then the two factors from that trinomial are the likely width and length, namely (3x + 1) (x - 4).

you can check them with FOIL.
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3 years ago
What is 9/8 in simplest from
Alchen [17]
9/8 is in the simplest form
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3 years ago
"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0
2 years ago
Please just help me im literally crying I dont want links to your math websites our teacher didnt teach us like half this stuff
8090 [49]

Answer:

Okay?

Step-by-step explanation:

I think m a week or 2 late

8 0
2 years ago
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