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Strike441 [17]
3 years ago
9

Which is NOT a type of basketball pass?

Physics
2 answers:
Scilla [17]3 years ago
6 0

Answer

1: Shoulder pass

2: Muscle

3: Tennis My bad!!

Arte-miy333 [17]3 years ago
5 0

Answer:

Shoulder Pass, Balance, Tennis

Explanation:

Shoulder Pass, Balance, Tennis

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Approximately how far is the sun from the center of the milky way galaxy?
enot [183]
The sun is approximately 27,000 light years away from the center of our galaxy.
8 0
3 years ago
Read 2 more answers
In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope
zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude g.

If we have the initial velocity v_o and its angle \theta, we can obtain the vertical component of the velocity v_{oy} using trigonometry:

v_{oy}=v_osin\theta

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

Finally, from the equation of horizontal motion with constant speed, we have that:

x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s}  }{9.8\frac{m}{s^{2} } } =7.49m

In words, the projectile travels 7.49m horizontally before it lands.

8 0
4 years ago
Benjamin recently issued new mobile phones to the marketing team at his company. Each phone can transmit encrypted information f
Misha Larkins [42]

Complete Question:

Which technology is set up on the marketing team's phones?

a) Bluetooth

b) Tethering

c) NFC

d) Hotspot

Answer:

NFC

Explanation:

Near Field Communication (NFC) is a short-range wireless connectivity standard that uses magnetic field induction to enable communication between devices when  brought within a few centimetres from each other. NFC offers a secured communication between connected electronic devices with simple setup that can be used to bootstrap more-capable wireless connections. It only covers a range of 10 cm to 20 cm.

None of the other options can transmit or share information for payments among the team except the NFC. NFC is also suitable for this setup because only a small range is expected to be covered.

4 0
3 years ago
IN THIS FORMULA FOR WATER WHAT DOES THE SUBSCRIPT 2 INDICATE
masha68 [24]
The chemical formular for water is H2O.
The H aspect of the formula stands for hydrogen gas and the subscript 2 which is attached to the H symbol signifies that two atoms of hydrogen are joined together, that is two atom of hydrogen are present.
The chemical formula of water indicates that, two atom of hydrogen react with one atom of oxygen to form one molecule of water.
In chemical formulae, subscripts are normally used to indicate the number of atoms that are present in a molecule.
7 0
4 years ago
What impulse occurs when an average force of 20-N is applied by a dad to a new bike riding child for 3.5 s. b) What change in mo
garri49 [273]

Answer:

A. 70 Ns

B. 70 Kgm/s

C. 2.19 m/s

Explanation:

A. Determination of the impulse.

Force (F) = 20 N

Time (t) = 3.5 s

Impulse (I) =?

Impulse (I) = force (F) × time (t)

I = Ft

I = 20 × 3.5

I = 70 Ns

Thus, the Impulse is 70 Ns.

B. Determination of the change in momentum

Force (F) = 20 N

Time (t) = 3.5 s

Change in momentum =?

Change in momentum = m(v – u) = Ft

Change in momentum = Ft

Change in momentum = 20 × 3.5

Change in momentum = 70 Kgm/s

C. Determination of the final velocity.

Change in momentum = 70 Kgm/s

Initial velocity (u) = 0 m/s

Combined mass (m) = 32 kg

Final velocity (v) =?

Change in momentum = m(v – u)

70 = 32(v – 0)

70 = 32(v)

70 = 32v

Divide both side by 32

v = 70 / 32

v = 2.19 m/s

Thus, the final velocity is 2.19 m/s

3 0
3 years ago
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