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<span>torque = rF
= 0.1(10)
=1 Nm</span>
1. 0.2 g/mL
The relationship between mass, density and volume of an object is
where
d is the density
m is the mass
V is the volume
For the object in this problem, we have
m = 10 g
V = 50 mL
Substituting into the equation,
2. 10 mL
In this exercise we know:
- The density of the object: d = 2 g/mL
- The mass of the object: m = 20 g
Therefore, we can re-arrange the previous equation to find the volume:
And substituting values into the equation, we find
First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
<h3>
First harmonic of a closed pipe</h3>
The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.
L = λ/4
where;
- L is the length of the pipe
- λ is the wavelength of sound
λ = 4L
But, v = F₀λ
v = F₀(4L)
F₀ = v/4L
where;
- F₀ is the first harmonic
- v is speed of sound
Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
Learn more about fundamental frequency here: brainly.com/question/1967686
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<h3 />
Well it seems that you did not give answer choices, but that its fine since we can use newtons law of universal gravitational, Fg = GM1M2/r^2. So G is the gravitational constant, which is 6.67*10^-11, we can plug in 6*1024 for M1, and 7*1022 for M2, and 3.8*108 for r. Which then we get 1.74 * 10^8 N as the force of attraction between the Earth and the moon.
