Answer:
y = (x -2)^2 +4
Step-by-step explanation:
The vertex form of the equation of a parabola is ...
y = a(x -h)^2 +k
for vertex (h, k) and vertical scale factor "a". When a > 0, the parabola opens upward.
One equation for your parabola could be ...
y = (x -2)^2 +4
__
In standard form this one is ...
y = x^2 -4x +8
Sorry, what grade is that for? might need to learn that right away
For this case, we must indicate which of the given functions is not defined for
By definition, we know that:
has a domain from 0 to infinity.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when
.
While
if it is defined for 
, your domain is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.
So, we have:
with x = 0:
is defined.
with x = 0:
in the same way is defined.
Answer:

Option b