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34kurt
3 years ago
9

What is 32×5/6 in simplest form

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0
32/1x5/6=160/6
6 goes into 160 26 times, with an extra 4.
Your answer is 26 4/6, or 26 2/3.
Hope this helps :-)
Zarrin [17]3 years ago
6 0
Your answer would be 80/3 

here are the steps 32• 5/6=

5/6•31/2=

160/6 
hope this helped
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Median mode mean and range on 84 45 10 28 75 63 16 55
GREYUIT [131]
PUT THIS SET IN ORDER FROM LEAST TO GREATEST:

10, 16, 28, 45, 55, 63, 75, 84
__________________
MEDIAN: Find the number in the middle of the set.
10, 16, 28, 45, 55, 63, 75, 84
There cannot be two medians, so you find the number between 45 & 55.
MEDIAN = 50
_________________
MEAN: Find the average by adding up all of the numbers and dividing them by how many numbers there are.
10 + 16 + 28 + 45 + 55 + 63 + 75 + 84 = 376
376/8 = 47
MEAN = 47
________________
MODE: The number that occurs most often. If no number repeats, there's no mode.
THERE IS NO MODE
________________
RANGE: The difference between the largest and smallest value in the set. Subtract the largest (84) and smallest (10) value.
84 - 10 = 74
RANGE = 74

6 0
4 years ago
Read 2 more answers
Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a)
Anna35 [415]

Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.

Given the function is f(x)=\sqrt{(2-x^{\frac{2}{3}})^{3}}  and the Rolle's Theorem does not apply to the function.

Rolle's theorem is used to determine if a function is continuous and also differentiable.

The condition for Rolle's theorem to be true as:

  • f(a)=f(b)
  • f(x) must be continuous in [a,b].
  • f(x) must be differentiable in (a,b).

To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.

If we look closely at the given function we can see that the first derivative of the given function is:

\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end

From this point of view we can see that the given function is not defined for x=0.

Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.

Learn more about Rolle's Theorem from here brainly.com/question/12279222

#SPJ4

8 0
2 years ago
Please help me with this I will give u 100 points
ValentinkaMS [17]

Answer:

see below

Step-by-step explanation:

Video Game

20% off means you pay 80%

80 dollars * 80% =

80 * .80 = 64

Movie ticket

14 original price

Sale price = 11.40

14* p% = 11.40

Divide each side by 14

p% = 11.40/14

p% =81.4285714

You paid 81 3/7%

The discount is 100 -81 3/7%

18 4/7 % discount

Laptop

1000 original price

Sale price = 750

1000 * p% = 750

p% = 750/1000

p% =75%

You paid 75%

The discount is 100 -75%

25 % discount

5 0
3 years ago
Read 2 more answers
What is the equivalent decimal to 1/2?
vova2212 [387]
0.5 is the decimal equivalent to 1/2
5 0
3 years ago
Read 2 more answers
40 tens.how many hundreds
Sladkaya [172]
400. Just add a zero when you're dealing with tens
7 0
3 years ago
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