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34kurt
3 years ago
9

What is 32×5/6 in simplest form

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0
32/1x5/6=160/6
6 goes into 160 26 times, with an extra 4.
Your answer is 26 4/6, or 26 2/3.
Hope this helps :-)
Zarrin [17]3 years ago
6 0
Your answer would be 80/3 

here are the steps 32• 5/6=

5/6•31/2=

160/6 
hope this helped
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What equation represents a parabola that opens UP with the vertex at 2,4
lubasha [3.4K]

Answer:

  y = (x -2)^2 +4

Step-by-step explanation:

The vertex form of the equation of a parabola is ...

  y = a(x -h)^2 +k

for vertex (h, k) and vertical scale factor "a". When a > 0, the parabola opens upward.

One equation for your parabola could be ...

  y = (x -2)^2 +4

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In standard form this one is ...

  y = x^2 -4x +8

3 0
3 years ago
Algebraically solve the system of equations shown below. Note that you can use either factoring or the quadratic formula to find
ivann1987 [24]
6x^2+19x-15=-12x+15\\
6x^2+31x-30=0\\
6x^2+36x-5x-30=0\\
6x(x+6)-5(x+6)=0\\
(6x-5)(x+6)=0\\
x=\frac{5}{6} \vee x=-6\\\\
y=-12\cdot\frac{5}{6} +15\vee y=-12\cdot(-6)+15\\
y=-10 +15\vee y=72+15\\
y=5 \vee y=87\\\\
x=\frac{5}{6} \wedge y=5\\
x=-6 \wedge y=87
7 0
3 years ago
Read 2 more answers
The Big Ben clock tower in London stands at a height of 316 feet. What is the metric equivalent in meters?
RideAnS [48]
96.31680m is the answer
5 0
3 years ago
Can someone please explain how to answer #18?
swat32
Sorry, what grade is that for? might need to learn that right away
4 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
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