Leo's bank balances at the end of months 1, 2, and 3 are $1,500.00, $1,530.00, and $1,560.60, respectively. The balances form a
2 answers:
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1. The area of the photograph is:
A=LxW
A is the area of the photograph (A=54 in²).
L is the lenght of the photograph (L=12-4x).
W is the widht of the photograph (W=12-2x)
2. When you substitute these values into the formula A=LxW, you obtain:
A=LxW
54=(12-4x)(12-2x)
3. When you apply the distributive property, you have:
54=144-24x-48x+8x²
8x²-72x+144-54=0
4. Finally, you obtain a quadratic equation for the area of the photo:
8x²-72x+90=0
5. Therefore, the answer is:
8x²-72x+90=0
A=LxW
A is the area of the photograph (A=54 in²).
L is the lenght of the photograph (L=12-4x).
W is the widht of the photograph (W=12-2x)
2. When you substitute these values into the formula A=LxW, you obtain:
A=LxW
54=(12-4x)(12-2x)
3. When you apply the distributive property, you have:
54=144-24x-48x+8x²
8x²-72x+144-54=0
4. Finally, you obtain a quadratic equation for the area of the photo:
8x²-72x+90=0
5. Therefore, the answer is:
8x²-72x+90=0