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EastWind [94]
3 years ago
7

Complete a prime factorization of 54 and write it as a product of primes

Mathematics
2 answers:
never [62]3 years ago
7 0
So to solve this you can break it down like this: 54 = 2 times 27. Two is a prime number so leave that alone. Next, 27 is 3 times 9. Three is a prime so leave that alone. Then 9 = 3 times 3. And both threes are prime. So take all the prime numbers, and there you have it! 3 times 3 times 3 times 2. Or 3 to the 3rd power times 2. Hope I helped.
kumpel [21]3 years ago
5 0
54
2 * 27
2 * 3 * 9
2 * 3 * 3 * 3 or 2 * 3^3 <==
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On Friday,1/6 of band practice was spent trying on uniforms.The band spent 1/4 of practice on marching.The remaining practice ti
Salsk061 [2.6K]

I mean I got 5/12 as my simplified answer but I might be wrong. I hope this helps in some way and sorry if I'm wrong

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2 years ago
Solve for a.<br> 4a+5=2+3.25a4a+5=2+3.25a
Rina8888 [55]

Answer:

a=-4

Step-by-step explanation:

4a-3.25a=2-5

0.75a=-3

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3 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

7 0
3 years ago
Al fotocopiar una credencial, primero se amplia al triple y posteriormente la copia resultante se reduce a la mitad. ¿Cual es el
ad-work [718]
Using google translate: 
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?

Original: 10 by 6 cm  ;  Area = length * width = 10 x 6 = 60 cm²

first copy: enlarged to triple
10 x 3 = 30 
6 x 3 = 18
30 x 18 = 540 cm²

second copy: halved
30 x 1/2 = 15
18 x 1/2 = 9
15 x 9 = 135 cm²


7 0
3 years ago
The tickets for an upcoming ballet cost $54 per person. Mrs. Anastos wants to purchase 16 tickets for her friends. What
MissTica

Answer:

the answer is $864 pls give brainliest

Step-by-step explanation:

5 0
3 years ago
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