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swat32
3 years ago
10

SIMPLIFY PLEASE.........................

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0
He can make fewer than 14 batches of cookies bc he could make 13 batches of cookies so it is B the second one. Hopefully this helped!!=“)
Pie3 years ago
4 0
He can make fewer than 14 batches of cookies.
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What is the solution to the equation 26=-d+6
Likurg_2 [28]
I believe the answer you are looking for is -20. 
7 0
3 years ago
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You notice a hot air balloon descending. The elevation h
ANEK [815]

Answer:

the domain is 0 x 45 and the range is 0 h 360. The slope is -8, so the change in the height of the ballon is -8 feet per second. The h-intercept is 360, so the height of the ballon when the first noticed it was 360 feet. The x-intercept is 45, so the time it took the hot air balloon to reach the ground was 45 seconds.

Step-by-step explanation:

8 0
3 years ago
6x – 4y = -5<br>4x + 5y = -11​
kipiarov [429]

Answer:

x= -1.5, y= -1

Step-by-step explanation:

6x= -5+4y

x= (-5+4y) / 6

4((-5+4y) / 6) + 5y = -11

4(-5+4y) + 5*6y = -11*6

-20+16y+30y= -66

16y + 30y = -66+20 = -46

y(16 + 30) = -46

y= -46 / (16 + 30)

y= -46 / 46

y= -1

x= (-5+4(-1)) / 6

x= (-5-4) / 6

x= -9 /6

x= -1.5

3 0
3 years ago
31 pizzas between 8 teams. How many pizzas does each team get?
IgorC [24]

Answer:

3.875 pizzas

Step-by-step explanation:

31/8=3.875

4 0
3 years ago
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Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
3 years ago
Read 2 more answers
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