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3 years ago

Decrease M720.00 by 25%

Mathematics

1 answer:

netineya [11]3 years ago

8 0

Answer:

540

Step-by-step explanation:

720 (100-25) to find the decimal to use (below 1.00 is decreasing)

720 (.75) = 540

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%3F%7D%7B5%7D%20%2A%20%5Cfrac%7B10%7D%7B8%7D%20%3D1.5%5C%5C" id="TexFormula1" title=

Serggg [28]

Answer:

$\boxed{\sf \huge \boxed{ \sf ?} = 6}$

Step-by-step explanation:

$\sf Solve \: for \: \boxed{ \sf ?} : \\ \sf \implies \frac{\boxed{ \sf ?}}{5} \times \frac{10}{8} = 1.5 \\ \\ \sf \implies \frac{\boxed{ \sf ?} \times 10}{5 \times 8} = 1.5 \\ \\ \sf \frac{10}{5} = \frac{ \cancel{5} \times 2}{ \cancel{5}} = 2 : \\ \sf \implies \frac{ \boxed{ \sf 2} \times \boxed{ \sf ?} }{8} = 1.5 \\ \\ \sf \frac{2}{8} = \frac{ \cancel{2}}{ \cancel{2} \times 4} = \frac{1}{4} : \\ \sf \implies \frac{\boxed{ \sf ?}}{ \boxed{ \sf 4}} = 1.5 \\ \\ \sf Multiply \: both \: sides \: of \: \frac{\boxed{ \sf ?}}{4} = 1.5 \: by \: 4 : \\ \sf \implies \frac{4 \times \boxed{ \sf ?}}{4} = 4 \times 1.5 \\ \\ \sf \frac{4 \times \boxed{ \sf ?}}{4} = \frac{ \cancel{4}}{ \cancel{4}} \times \boxed{ \sf ?} = \boxed{ \sf ?} : \\ \sf \implies \boxed{\boxed{ \sf ?}} = 4 \times 1.5 \\ \\ \sf 4 \times 1.5 = 6 : \\ \sf \implies \boxed{ \sf ?} = 6$

4 0

3 years ago

Savannah's biweekly salary is $3010.What is her annual salary?

irga5000 [103]

Answer: $78,260

Explanation:

is her annual salary bi annually means ever two weeks and 52 weeks in a year so u divide 52 by two and multiply that by her biweekly salary

8 0

3 years ago

Write each power as a product of the Same factor then find the value 1. 4^3 2. 2^6 3. 8^4 4. 12^2

qwelly [4]

Answer:

15^3=15×15×15=3375

0^4=0×0×0×0=0

5^5=5×5×5×5×5=3125

3.5^2=3.5×3.5=12.25

6^5=6×6×6×6×6=7776

7^4=7×7×7×7=2401

1^8=1×1×1×1×1×1×1×1=1

2.5^3=2.5×2.5×2.5=15.625

Step-by-step explanation:

7 0

3 years ago

Help!!! Algebra 2<br> :( Due in 7Mins

LekaFEV [45]

Answer

Step-by-step explanation: The chain rule states that the derivative of f(g(x)) is f'(g(x))⋅g'(x). In other words, it helps us differentiate *composite functions*.

8 0

3 years ago

Use the associative law of multiplication to write an equivalent expression. <br> 9[m(6+n)]

jek_recluse [69]

The associative law states that it doesn't matter how we group numbers when we add and/or multiply. So we could rearrange the brackets and parentheses to get the equivalent equation:
9m(6+n)

Both equations total:
54m+9mn
(I applied the distributive property to solve it).

8 0

3 years ago