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Answer:
Phenotypes of offsprings: Type A, Type B
Explanation:
This question involves a single gene for blood group in humans. The ABO blood group system consist of three alleles: A, B, and O. A and B are dominant over O but co-dominant to one another.
If a woman with type O blood (OO) has a child with a male with type AB blood (AB) i.e OO × AB, the following gametes will be produced by each parent:
OO - O
AB - A and B
Using these gametes in a punnet square (see attached image), the offsprings with the following genotyoes will be produced: AO (2), BO (2)
AO - phenotypically type A
BO - phenotypically type B
Hence, a type A and type B blood group offsprings will be produced.
Answer:
a) All males will have dark wings, all females will have light wings. See attachment
b) Males - 50:50 dark:light, females, 100% dark wings
Explanation:
The ZW sex determination system is different from the XY sex determination system. Females are ZW, whereas males are ZZ (in contrast to XY system where females have two of the same chromosome [XX] and males have two different ones [XY]).
a) The potential genotypes of the F1 are shown in attachment. This shows that all males will have dark wings (Ll) (all heterozygous) and all females will have light wings (l) (all will inherit l allele from father)
b) The potential genotypes of the F2 are shown in attachment. This shows that 50% of the males will have light wings (Ll), and 50% will have dark wings (ll). All of the females will have dark wings (L).
