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3 years ago

Find the value of x in the triangle shown below.

Mathematics

1 answer:

BARSIC [14]3 years ago

5 0

Answer:

x=12

Step-by-step explanation:

Since this is a right triangle we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

9^2 + x^2 = 15^2

81 + x^2 = 225

Subtract 81 from each side

x^2 =225-81

x^2 =144

Take the square root of each side

sqrt(x^2) = sqrt(144)

x=12

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In a year group there 100 boys and 140 girls. Write as a ratio the number of boy to the number of girls. Give the answer in the

expeople1 [14]

no. of boys : no.of girls

100 : 140

to get the simplest ratio you gotta divide both with a common factor

Because both 100 and 140 share a common factor of 20

the simplest ratio will be

100/20 : 140/20

5:7

5:7 is the simplest ratio

5 0

2 years ago

Read 2 more answers

What is the constant term of -3x^4-7x+2

san4es73 [151]

Answer:

The answer is 2. 2 is the only number that can't change. There is no x or ^.

4 0

3 years ago

Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

3 years ago

FIND VALUEE OF Y !!!

Mazyrski [523]

Answer:

Step-by-step explanation:

9y+12=75

subtract 12 from 75

divide by 9y

5 0

3 years ago

The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid

ryzh [129]

Given:

The bases of a trapezoid lie on the lines

$y=2x+7$

$y=2x-5$

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

On comparing $y=2x+7$ with slope intercept form, we get

$m_1=2,b_1=7$

On comparing $y=2x-5$ with slope intercept form, we get

$m_2=2,b_2=-5$

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

$m=m_1=m_2=2$

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

$b=\dfrac{b_1+b_2}{2}$