The distance formula is a the key element in the proof of which of the following?

you deposited $5500 in a account that pays 3.6% annual interest. find the balance after 2 years if the interest is compound mont

Sedaia [141]

Answer:

$5,909.97

Step-by-step explanation:

We will use the compound interest formula for this problem as shown below:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 3.6% into a decimal:

3.6% -> $\frac{3.6}{100}$ -> 0.036

Now plug in the values:

$A=5,500(1+\frac{0.036}{12})^{12(2)}$

$A=5,909.97$

After 2 years, the balance would be $5,909.97

6 0

3 years ago

Burton travels on cruise control at 50 mph from 2:00 p.m. until 5:00 p.m. How far does he travel?

galina1969 [7]

Answer: no

Step-by-step explanation:

7 0

4 years ago

Crash testing evaluates the ability of an automobile to withstand a serious accident. A simple random sample of 12 small cars we

morpeh [17]

Answer:

The 95% confidence interval for the difference between proportions is (-0.046, 0.713).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (small cars), of size n1=12 has a proportion of p1=0.6667.

$p_1=X_1/n_1=8/12=0.6667$

The sample 2, of size n2=15 has a proportion of p2=0.3333.

$p_2=X_2/n_2=5/15=0.3333$

The difference between proportions is (p1-p2)=0.3333.

$p_d=p_1-p_2=0.6667-0.3333=0.3333$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{8+5}{12+15}=\dfrac{13}{27}=0.4815$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.4815*0.5185}{12}+\dfrac{0.4815*0.5185}{15}}\\\\\\s_{p1-p2}=\sqrt{0.0208+0.0166}=\sqrt{0.0374}=0.1935$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.1935=0.3793$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.3333-0.3793=-0.046\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.3333+0.3793=0.713$

The 95% confidence interval for the difference between proportions is (-0.046, 0.713).

8 0

4 years ago

What is the area of the figure below? 3 5/6in 6in

atroni [7]

Answer:

120

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1) using maths induction

crimeas [40]

Hello,

$if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\$

We suppose the property true for n:

1²+2²+...+n²=n(n+1)(2n+1) / 6

and we are going to demonstrate that the property is true for n+1:

1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6

$1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\$

5 0

3 years ago