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Kipish [7]
3 years ago
13

I need some help with this one :)

Physics
1 answer:
SVEN [57.7K]3 years ago
3 0

Explanation:

I think so c is answer

good morning

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Amanda [17]

Answer:

When mass is greater, the force needed must be greater keeping the acceleration of the wheel chair constant

Explanation:

force = mass \times acceleration \\ f \:  \alpha  \: m

force is directly proportional to the mass

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3 years ago
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For two objects in space with very different masses, the gravitational force causes:
guajiro [1.7K]
The answer is B. The less massive object to orbit the more massive object.
Explanation: The more massive the object, the larger its gravitational pull.
Example: the moon orbits the earth because the moon’s mass is smaller than earth, earth orbits the sun because the earth’s mass is smaller than the sun..
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2 years ago
Please help
inysia [295]

Explanation:

Start with what you know and list your knowns and unknowns

F = ma

F= 3N

m = 6kg

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3 0
3 years ago
What is an example of a non contact force
olchik [2.2K]

Answer: Gravitational force

Explanation:

A non contact force can be described as a force applied to an object by another body that is not in direct contact with it.

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8 0
4 years ago
A 0.106-A current is charging a capacitor that has square plates 4.60 cm on each side. The plate separation is 4.00 mm.
nikdorinn [45]

Answer:

a

 \frac{d \phi_{E}}{dt}  =1.1977 *10^{10} \  V\cdot m/s

b

 I = 0.106 \  A

Explanation:

From the question we are told that

  The current is  I =  0.106 \  A

   The length of one side of the square a = 4.60 \  cm = 0.046 \  m

    The separation between the plate is  d = 4.0 mm  = 0.004 \ m

Generally electric flux is mathematically represented as

       \phi_E = \frac{Q}{\epsilon_o}

differentiating both sides with respect to t is  

       \frac{d \phi_{E}}{dt}  = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}

=>     \frac{d \phi_{E}}{dt}  = \frac{1}{\epsilon_o} *I

Here \epsilon_o is the permitivity of free space with value  

        \epsilon _o  =  8.85*10^{-12} C/(V \cdot m)

=>   \frac{d \phi_{E}}{dt}  = \frac{0.106}{8.85*10^{-12}}

=>   \frac{d \phi_{E}}{dt}  =1.1977 *10^{10} \  V\cdot m/s

Generally the displacement current between the plates in A

    I = 8.85*10^{-12} * 1.1977 *10^{10}

=>  I = 0.106 \  A

 

3 0
3 years ago
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