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Anna [14]
3 years ago
13

Please help

Physics
1 answer:
inysia [295]3 years ago
3 0

Explanation:

Start with what you know and list your knowns and unknowns

F = ma

F= 3N

m = 6kg

a =?

3N = 6kg x a

solve for a

3N / 6kg = a

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Most nebulae are of vast size, even hundreds of light years in diameter.[3] Although denser than the space surrounding them, most nebulae are far less dense than any vacuum created on Earth – a nebular cloud the size of the Earth would have a total mass of only a few kilograms. Many nebulae are visible due to their fluorescence caused by the embedded hot stars, while others are so diffuse they can only be detected with long exposures and special filters. Some nebulae, are variably illuminated by T Tauri variable stars. Nebulae are often star-forming regions, such as in the "Pillars of Creation" in the Eagle Nebula. In these regions the formations of gas, dust, and other materials "clump" together to form denser regions, which attract further matter, and eventually will become dense enough to form stars. The remaining material is then believed to form planets and other planetary system objects.

The range of objects called nebula are very diverse, have diverse origins, and final ends.

Contents <span> [hide] </span><span><span>1Observational history</span><span>2Formation</span><span><span>3Types of nebulae</span><span><span>3.1Classical types</span><span>3.2Diffuse nebulae</span><span><span>3.3Planetary nebulae</span><span>3.3.1Protoplanetary nebula</span></span><span>3.4Supernova remnants</span></span></span><span><span>4Notable named nebulae</span><span>4.1Nebula catalogs</span></span><span>5See also</span><span>6References</span><span>7<span>External links

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4 years ago
What color of light in the visible spectrum appears brightest?
VLD [36.1K]
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4 0
3 years ago
A GPS receiver can tell you your exact latitude and longitude?
Dmitry_Shevchenko [17]
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3 0
3 years ago
What is the frequency of light for which the wavelength is 7.1 × 102 nm?
Brilliant_brown [7]

Answer:

Frequency, f=4.22\times 10^{14}\ Hz

Explanation:

Given that,

Wavelength of the light,

\lambda=7.1\times 10^2\ nm=7.1\times 10^2\times 10^{-9}\ m\\\\\lambda=7.1\times 10^{-7}\ m

We need to find the frequency of light. We know that light is an electromagnetic wave. It moves with the speed of light. So,

c=f\lambda

f is the frequency of light

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8\ m/s}{7.1\times 10^{-7}\ m}\\\\f=4.22\times 10^{14}\ Hz

So, the frequency of light is 4.22\times 10^{14}\ Hz. Hence, this is the required solution.

5 0
4 years ago
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