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Setler [38]
2 years ago
10

Which is function? I got them wrong except for 1. I’ll give brainlist :)

Mathematics
2 answers:
ipn [44]2 years ago
8 0

Answer:

The second graph is a function; third one is not

Step-by-step explanation:

Well, you can do the vertical line test. Basically draw a vertical line and see if there are 2 lines intersecting that one vertical line. If it is, it is not a function.

Hope this helps :)

-jp524

Elanso [62]2 years ago
6 0

Answer:

2 is a function and 3 isn't a function

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
Which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?​
Alex Ar [27]

Answer:

\frac{x^2}{12}-\frac{y^2}{4}=1

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

  • <u />\frac{x^2}{a^2}-\frac{y^2}{b^2}=1
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Since we are given our directrices of x=\pm3 and foci of (\pm4,0), then we can set up the directrices equation to solve for a^2:

x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2

Now we can determine b^2 to complete our equation for the hyperbola:

a^2+b^2=c^2\\\\12+b^2=4^2\\\\12+b^2=16\\\\b^2=4

Therefore, our equation for our hyperbola is \frac{x^2}{12}-\frac{y^2}{4}=1

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Answer:

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Step-by-step explanation:

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b = -4+6 = 2

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