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Mathematics

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Anna35 [415]1 year ago

6 0

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Point B is on line segment \overline{AC}

MA_775_DIABLO [31]

I really can’t help you but I’ll wish look for you

3 0

2 years ago

The coefficient of determination is used to: compute correlations for truncated ranges. compare the relative strength of coeffic

kozerog [31]

Answer: compare the relative strength of coefficients.

Step-by-step explanation: The Coefficient of determination usually denoted as R^2 is obtained by taking the squared value of the correlation Coefficient (R). It's value ranges from 0 to 1 and the value obtained gives the proportion of variation in the dependent variable which could be attributed to it's correlation or relationship to th independent variable. With a R^2 value close to 1, this means a large portion of Variation in a variable A could be explained due to changes in variable B while a low value signifies a low variance between the variables. Hence, the Coefficient of determination is used in comparing the relative strength of the Coefficients in other to establish whether a weak or strong relationship exist.

6 0

2 years ago

The solution set of 2-3x/4-8=3x/4

deff fn [24]

Step-by-step explanation:

$\\ \tt{:}\leadsto \frac{2 - 3x}{4 - 8} = \frac{3x}{4} \\ \\ \tt{:}\leadsto 4(2 - 3x) = 3x(4 - 8) \\ \\ \tt{:}\leadsto 8 - 12x = 3x( - 4) \\ \\ \tt{:}\leadsto 8 - 2x = - 12x \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt{:}\leadsto 8 = - 12x + 2x \\ \\ \tt{:}\leadsto 8 = - 10x \\ \\ \tt{:}\leadsto x = \frac{ - 10}{8} \\ \\ \tt{:}\leadsto x = \frac{ - 5}{4}$