Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
y
=
−
2
x
+
9
Step-by-step explanation:
Write in slope-intercept form, y
=
m
x
+
b
.
Answer:
6000
Step-by-step explanation:
Answer:
15 x 10^-1
Step-by-step explanation:
36÷24=1.5
In this case I'm considering 15 as the base of my standard form.
To make 15 a 1.5, you'll have to move from right to left one unit and on the number line moving from the right to left gives you a negative number of units moved
Answer:
40 miles per hour
Step-by-step explanation:
80 divided by 2 is 40
160 divided by 4 is 40