Answer:
check below
Step-by-step explanation:
1. c = 68-27 = 41
2. t = 7.9+1.5 =9.4
3. a = 21*3 = 63
4. (multiply whole equation by 8) 8r+6=7, r=1/8
5. x = 25.2/4.2 = 6
6. b = 75/15 = 5
7. A. 6C = 99
B. C = 99/6 = $16.50
The solution represents the cost of one ticket.
Answer:
Step-by-step explanation:
With reference < H
perpendicular (p) = 12
base (b) = 5
so now
tangent of < H
= p / b
= 12 / 5
hope it helps :)
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
<em>x = -6</em>
Step-by-step explanation:
<u>Equations</u>
Solve the equation:
x + 6 = -x - 6
We must find the value of x that makes the identity above true.
Let's join all the variables on the left side and the numbers on the right side.
Adding x:
x + 6 + x = -x - 6 + x
The variables cancel out on the right side:
2x + 6 = -6
Subtracting 6:
2x + 6 - 6 = -6 -6
The 6 and -6 are canceled out:
2x = -12
Dividing by 2:
x = -12/2
x = -6
