Answer:
c
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here m = 3 and c = 2, thus
y = 3x + 2 → c
<span>We write the equation in the standard form which is:
ax^2 + bx + c = 0
(x + 15)(x) = 100
x^2 + 15x - 100 = 0
(x + 20) (x-5) = 0
The solutions are
x = -20 and x = 5
Therefore, the correct answer is option B. </span><span>The solution x = 5 should be kept, but x = –20 is unreasonable.</span><span>
</span>
Answer:
maybe x=0=>y=1 or maybe x=0=>y=-2
Answer: y = -(9/5)x - 1
Step-by-step explanation:
Rewrite the equation in standard form: y = (5/9)x+(8/9). [y=mx+b]
A line perpendicular to this would have a slope that is the negative inverse of the original slope (5/9), which would make it -(9/5). The y-intercept would also change, but we don't know the value, yet. For now, we'll use "b" for the y-intercept. This results in a perpendicular line:
y = -(9/5)x + b
We can calculate b, the y-intercept, by using the point (-5,8) and solving for b.
8 = -(9/5)*(-5) + b
8 = (9) + b
b = -1
The line perpendicular to 5x−9y=−8 that passes through the point (−5,8) is
y = -(9/5)x - 1
Answer:
the answer I got is p=-176/3 that's the only answer I got