Answer:
CI(99%) = ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
Critical value z(at 99% confidence) = z(0.005) = 2.58
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean gain x = 1.5
Standard deviation r = 0.58
Number of samples n = 7
Confidence interval = 99%
Critical value z(at 99% confidence) = z((1-0.99)/2)
z(0.005) = 2.58
Substituting the values we have;
1.5+/-2.58(0.58/√7)
1.5+/-2.58(0.2192)
1.5+/-0.565536
1.5+/-0.57
= ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
The formula is
A=p (1+rt)
A cost of the car 13080
P amount deposited 12000
R interest rate 0.03
T time?
Solve for t
T=[(A/p)-1]÷r
T=((13,080÷12,000)−1)÷0.03
T=3 years
Answer:
D
Step-by-step explanation:
Hope this helped! Please tell me if I'm wrong!
Answer:
6
Step-by-step explanation:
4 = 24 / 6
Answer:
Step-by-step explanation:
<u>Given data:</u>
Base = b = 4 cm
Height = h = 4 cm
<u>Required:</u>
Area of triangle = A = ?
<u>Formula:</u>
A = bh / 2
<u>Solution:</u>
A = (4)(4) / 2
A = 16 / 2
A = 8 cm²
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
