All categories

2 years ago

The ratio of boys to girls in a class is 5:4. There are 36 Students in the class.How many students are girls

Mathematics

2 answers:

Brums [2.3K]2 years ago

6 0

Answer:

Step-by-step explanation:

let boys equal to 5x

and girls equal to 4x

so 4x+5x=36

X=4

so boys are 5*4

boys are 20

and girls are 16

so boys are 4 more than girls

babymother [125]2 years ago

3 0

Answer:

16 girls

Step-by-step explanation:

boys : girls : total

5 4 5+4 = 9

take the total number of people and divide by 9

36/9 = 4

Each number should be multiplied by 4

boys : girls : total

5*4 4*4 9*4

20 16 36

There are 16 girls

You might be interested in

In testing the difference between two population means using two independent samples, the sampling distribution of the sample me

Neko [114]

Answer:

C. populations are non normal and the sample sizes are large.

Step-by-step explanation:

To test hypotheses about the difference between two populations means we deal with the following three cases.

1) both the populations are normal with known standard deviations.

2)both the populations are normal with unknown standard deviations.

3) both the populations are non normal in which case both the sample sizes are necessarily large.

So option C is the correct answer.

4 0

3 years ago

180 clockwise around point (0,1)

sweet-ann [11.9K]

I think it is (0,-1)

3 0

2 years ago

Read 2 more answers

Find the x-coordinates where f ' (x)=0 for f(x)=2x+sin(4x) in the interval [0, pi]

MAVERICK [17]

Answer:

The x-coordinate is \dfrac{\pi}{6}[/tex].

Step-by-step explanation:

We are given a function f(x) as:

$f(x)=2x+\sin (4x)$

Now on differentiating both side with respect to x we get that:

$f'(x)=2+4 \cos (4x)$

When $f'(x)=0$

this means that $2+4\cos (4x)=0\\\\4\cos (4x)=-2\\\\\cos(4x)=\dfrac{-1}{2}$

Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval $[0,\pi]$ .

also we know that $\cos (\dfrac{2\pi}{3})=\dfrac{-1}{2}$ ----(1) (which lie in the second quadrant)

so on comparing our equation with equation (1) we obtain:

$4x=\dfrac{2\pi}{3}\\\\x=\dfrac{\pi}{6}$

Hence, the x-coordinates where $f'(x)=0$ for $f(x)=2x+\sin(4x)$ is $\dfrac{\pi}{6}$ .

5 0

3 years ago

#3 Can someone please help me with these questions!!!!

rosijanka [135]

Answer:

Option A 90,68

$m\angle 1=90^o$

$m\angle 2=68^o$

Step-by-step explanation:

see the attached figure to better understand the problem

The figure shows a kite

we know that

A kite properties include

1) two pairs of consecutive, congruent sides

2) congruent non-vertex angles

3) perpendicular diagonals

Find the measure of angle 1

we have that

$m\angle 1=90^o$ ----> by the diagonals are perpendicular

Find the measure of angle 2

we know that

triangle AEB is congruent with triangle CEB

$m\angle EAB=m\angle ECB=m\angle 2$

In the right triangle EAB

$m\angle EAB+22^o=90^o$ ----> by complementary angles in a right triangle

$m\angle EAB=90^o-22^o=68^o$

therefore

$m\angle 2=68^o$

7 0

3 years ago

What is the product?<br><br> 2x(x – 4)

sashaice [31]

Keywords:

<em>Product, factors, polynomial, distributive property </em>

For this case we must find the product of two factors of a polynomial. To do this, we must apply the distributive property, which states: $a (b + c) = ab + ac.$

So:

$2x (x - 4) = 2x * x-2x * 4\\2x (x - 4) = 2x ^ 2-8x$

Thus, the product of $2x (x - 4)$ is: $2x ^ 2-8x$

Answer:

The product of $2x (x - 4)$ is: $2x ^ 2-8x$

6 0

3 years ago

Read 2 more answers