Answer:
how many does he have???
Step-by-step explanation:
I'm only going to complete Part B. The other two are a bit easier and I believe you can do it! :D
Neighborhood A
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Year 1: 30 increased by 20% = 6 more homes.
Year 2: 36 increased by 20% = 7.2 more homes ... 7 more homes. You cannot round in these types of problems.
Year 3: 43 increased by 20% = 8.6 ... 8 more homes.
Year 4: 51 increased by 20% = 10.2 ... 10 more homes.
Year 5: 61 increased by 20% = 12.2 ... 12 more homes.
At the end of 5 years Neighborhood A will have 73 homes in total.
Neighborhood B
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Year 1: 45 +3 = 48
Year 2: 48 +3 = 51
Year 3: 51 +3 = 54
Year 4: 54 +3 = 57
Year 5: 57 +3= 60 homes
After 5 years Neighborhood B will have 60 homes.
Hope this helped! I will do Part A or Part C later if I have time and you still need assistance.
Answer:
8.239x10^-5
so the answer is A
Step-by-step explanation:
trust me
ps. use photomath on phone
Answer: $38
Step-by-step explanation:
you have add 20 & 18 which would give you 38
M.N and O are 60 degree. And you have to know that 30 60 and 90 triangle. if 30 degrees opposite is measuring A , 60 is A square root 3 and the 90's opposite is being 2A. So 90 degree opposite is 16 square root 3 and 30 degree is being 8 square root 3 and 60 is
the height is 24 .
