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Andrew [12]
3 years ago
10

Solve. −14y=16 64 4 ​−4 ​ ​−64 ​

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

Step-by-step explanation:

-14y = 16

-14y = 16

________

-14       -14

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Suppose your car has hhh liters of engine oil in the morning. During the day, some oil may have leaked, you may have added more
Igoryamba

Answer:

g = (h+a) - l

None of them

Step-by-step explanation:

Suppose your car has h liters of engine oil in the morning. During the day, some oil may have leaked, you may have added more oil, or both. The oil level in the evening is g liters. Which of the following expressions always represents how far away the new oil level is from the previous oil level? H+G lGl none of them

Let

h = liters of oil in the morning

l= liters that has leaked

a= liters that were added during the day

g= amount of liters at the end of the evening

Total liters of oil in the evening= (litres of oil in the morning + litres of oil added during the day) - litres of oil that leaked

Substituting each variable into the formula, we have

g = (h+a) - l

3 0
3 years ago
The difference between 7 7/8 - 3 1/4
Dima020 [189]
You could convert them into improper fractions first. 7 7/8 should become 63/8 and 3 1/4 should become 13/4. Then, change both fractions so they share a common denominator. I'll use 8. 
63/8-26/8 = 37/8, which is then converted into 4 5/8.
Hope that helped you.
8 0
3 years ago
Read 2 more answers
Helppp I just need it to be explained. #7
IceJOKER [234]
#7 is the easiest one.

a + bi = -9 + 4i

see the expression on either side matches up so..
 a = -9 and b = 4
5 0
3 years ago
PERSEVERE Find the values of x and y,
Vlad [161]

y² = 8y - 15 (alternate angles are equal)

y² - 8y + 15 = 0

(y - 5)(y - 3) = 0

y = 5 or 3

x + 8y - 15 = 180 (angles in a straight line add up to 180)

when y = 5

x + 40 - 15 = 180

x = 155°

when y = 3

x + 24 - 15 = 180

x = 171°

8 0
3 years ago
H=7+44t-16^2
djyliett [7]

Answer:

t_1\approx2.18

t_2\approx0.57

Step-by-step explanation:

h=7+44t-16t^2

27=7+44t-16t^2

0=-20+44t-16t^2

0=-16t^2+44t-20

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

t=\frac{-44\pm\sqrt{44^2-4(-16)(-20)}}{2(-16)}

t=\frac{-44\pm\sqrt{1936-1280}}{-32}

t=\frac{-44\pm\sqrt{656}}{-32}

t=\frac{-44\pm4\sqrt{41}}{-32}

t=\frac{11}{8}\pm\frac{\sqrt{41}}{8}

t_1\approx2.18

t_2\approx0.57

5 0
2 years ago
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