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Andrew [12]
3 years ago
10

Solve. −14y=16 64 4 ​−4 ​ ​−64 ​

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

Step-by-step explanation:

-14y = 16

-14y = 16

________

-14       -14

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Suppose you are conducting a survey about the amount grocery store baggers are tipped for helping customers to their cars .for a
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Using the Empirical Rule and the Central Limit Theorem, we have that:

  • About 68% of the sample mean fall with in the intervals $1.64 and $1.82.
  • About 99.7% of the sample mean fall with in the intervals $1.46 and $2.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

<h3>What does the Central Limit Theorem state?</h3>

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the standard deviation of the distribution of sample means is:

s = \frac{0.657}{\sqrt{50}} = 0.09

68% of the means are within 1 standard deviation of the mean, hence the bounds are:

  • 1.73 - 0.09 = $1.64.
  • 1.73 + 0.09 = $1.82.

99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:

  • 1.73 - 3 x 0.09 = $1.46.
  • 1.73 + 3 x 0.09 = $2.

More can be learned about the Empirical Rule at brainly.com/question/24537145

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The 12 boys in the class make up 15% of the class. What is the total number of students in the class?
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Answer:

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Step-by-step explanation:

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Answer: (-6, 5)

<u>Step-by-step explanation:</u>

Use the Midpoint Formula: \dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)

Separate the x's and y's and solve them individually:

\dfrac{x_k+x_L}{2}=x_m\qquad \qquad \qquad \qquad\dfrac{y_k+y_L}{2}=y_m\\\\\\\dfrac{x_k+8}{2}=1\qquad \qquad \qquad \qquad \qquad \dfrac{y_k-7}{2}=-1\\\\\\x_k+8=2\qquad \qquad \qquad \qquad \qquad y_k-7=-2\\\\\\x_k\quad =-6 \qquad \qquad \qquad \qquad \qquad y_k\qquad =5

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