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3 years ago

I need help, am not good at this

Mathematics

1 answer:

dem82 [27]3 years ago

5 0

Answer:

If z =1/2, which expression has the greatest value?

1. (z^-2 z^5)^-2 = (z^3)^-2 = 1/z^6 = 1/(1/2)^6 = 2^6 = 64

2. (z^3)^5 = z^15 = (1/2)^15 = 1/(2^15)

3. z^-6 z^4 = z^-2 = (1/2)^-2 = 1/2^2 = 1/4

4.-(z^2 z^-4)^-3 is negative 64

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14=s/3 what does s equal

Juliette [100K]

You have to do the inverse of divide so multiply to find out a

14x 3= 42

S= 42

5 0

3 years ago

Read 2 more answers

Determine the volume of a cylinder with 251.20cm2 lateral area and 78.50cm2 base area

horrorfan [7]

Answer:

Answer is 628 cm^3

Step-by-step explanation:

using base area lets find radius

base area=pie*(r)^2

78.50=3.14*r^2

78.50/3.14=r^2

25=r^2

5=r

now using lateral area lets find height

lateral area=2*pie*r*h

251.20=2*3.14*5*h

251.20=31.4*h

251.20/31.4=h

8=h

volume of cylinder=pie*(r)^2*h

=3.14*(5)^2*8

3.14*25*8

=628 cm^3

3 0

2 years ago

Please answer the attached question by selecting of the the given answers.

Alchen [17]

Answer:

The correct answer is option A. Base = 11 cm and height = 13 cm

Step-by-step explanation:

It is given that, height of a triangle is 2 cm more than its base.Then height is increased by 2 cm.Then the area of triangle becomes 82.5 cm²

<u>To find the base an d height of original triangle</u>

Let x be the original base 'b' then the height h = x + 2

New height h = x + 2 + 2 = x + 4

Area = bh/2

82.5= (x(x + 4)/2

165 = x² + 4x

x + 4x - 165 = 0

Solving we get x = 11 and x = -15

Take positive value x = 11

Therefore base = 11 and height = x + 2 = 13 cm

The correct answer is option A. Base = 11 cm and height = 13 cm

5 0

3 years ago

PLEASE ANSWER ALL I WILL GIVE BRAINLIEST

sineoko [7]

0,0 1,3 2,4 3,8 4,5 5,5 6,2 7,0 hope that helps

6 0

3 years ago

Read 2 more answers

On a piece of paper, graph y>x-1. Then determine which answer choice

zepelin [54]

The graph that matches the given equation is y≥x-1 is Graph A.

Option: C.

<u>Step-by-step explanation:</u>

The given equation y≥x-1 is a linear inequality equation.

Graphing Linear Inequalities differs from graphing regular linear equations. That is it has certain rules to be followed to draw the graph.

First, rearrange the equation as y in the left and other terms in the opposite side.
Check for the line: y= , y≤ and y≥ comes with straight line where as y< and y> comes with a dotted line.
Shading: If y> greater than or y≥ greater than or equal is present then the space above the line has to be shaded. If y< less than or y≤ less than or equal is present then the space below the line has to be shaded.

For the given equation y≥x-1,

The line will be solid passing through (0,-1) and (3,2) since it has y≥. Also, the region above the line is shaded.

So the graph A is the graph that matches the equation y≥x-1.

8 0

3 years ago