The expression obtained after solving the given expression is,
<h3>What is a BODMAS rule?</h3>
For the Bracket, Order, Division, Multiplication, Addition, and Subtraction rules, BODMAS stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction.
Given expression ;
9(5x + 1) ÷ 3y
Follow the BODMAS rule;
Step 1; Divide

Step 2; Multiply

Hence the expression obtained after solving the given expression is,
To learn more about the BODMAS rule, refer to brainly.com/question/23827397.
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Justify means plug answer in and verify
so distribute 8(3-7x)=24-56x
143=7+24-56x
143=31-56x
minus 31 both sides
112=-56x
divide both sides by -56
-2=x
justify
plug it back
143=7+8(3-7x)
143=7+8(3-7(-2))
143=7+8(3-(-14))
143=7+8(3+14)
143=7+8(17)
143=7+136
143=143
true
x=-2
The value of 4 is Hundreds.
Your welcome
Answer:

Step-by-step explanation:
<u>Exponents Properties</u>
We need to recall the following properties of exponents:


We are given the expression:

We need to express the following expression in terms of n.

It's necessary to modify the expression to use the given equivalence.
Recall
. Thus:

Applying the property:

Substituting the given expression:

Or, equivalently:
