Answer:
Step-by-step explanation:
Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.
Height of male pilot = 74.2 inches
We have to find the percentile
X = 74.2
Corresponding Z score = 74.2-72.6 = 1.6
P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%
i.e. only 5% are below him in height.
Thus the malepilot is in 5th percentile.
Answer:
b i think
Step-by-step explanation:
To figure this out i would just dived 2.8 by 3 then multiply by two. I do not know if you must keep it as a fraction but this is the easiest way for me to do it
