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In-s [12.5K]
3 years ago
12

I am having trouble with this problem. If anyone could help that would be great.

Mathematics
1 answer:
lara [203]3 years ago
5 0

Answer:

Ok... I hope this is correct

Step-by-step explanation:

Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^(2)+y^(2)=16

Center:  ( 0 , 0 )

Vertices:  ( 4 , 0 ) , ( − 4 , 0 )

Foci:  ( 4 √ 2 , 0 ) , ( − 4 √ 2 , 0 )

Eccentricity:  √ 2

Focal Parameter:  2 √ 2

Asymptotes:  y = x ,  y = − x

Then 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1.

Simplified

0 ≤ z ≤ 1 , x ^2 + y ^2 + z ^2 − 2 ^z + 1 = 16 , z ≥ 1

For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.

Vector:

csc ( x )  ,  x = π

cot ( 3 x )  ,  x = 2 π 3

cos ( x 2 )  ,  x = 2 π

Since  

( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x ^2 )  is constant with respect to  F , the derivative of  ( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x 2 )  with respect to  F  is  0 .

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A tree farm owner uses a grid to mark where to plant trees in the spring. The first tree is planted at (2, 3). Each of the other
Tatiana [17]

Answer:

See attached image for the drawing of the first four trees (circled in green)

The patterns is:

x = 2+3n  and  y= 3+2n

Position of 7th tree is: (20,15) (circled in orange in the image)

Step-by-step explanation:

Starting at the location (2,3) the next x and y positions are given by:

x = 2+3n since the horizontal position needs to be increased by 3 units on each iteration,

and y= 3+2n since the vertical position needs to be increased by 2 units on each iteration

being n= 1 through 6 (to account for the next 6 trees that need to be planted)

With such pattern, the location of the seventh tree would be:

x = 2 + 3*6 =2 + 18 = 20

y = 3 + 2*6 = 3 + 12 = 15

That is, the point (20,15) on the plane.

Also see attached image.

8 0
3 years ago
Factor completely 3bx^2 - 9x^3 - b + 3x​
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Factor out the common terms in the first two terms, then in the last two terms;

3x^2(b - 3x) - (b - 3x)

Factor out the common term b - 3x

<u>= (b - 3x)(3x^2 - 1)</u>

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3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

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Afina-wow [57]

Answer:

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Step-by-step explanation:

7 0
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Ira Lisetskai [31]

Answer:

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Step-by-step explanation:

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1.5 ft = 18 in

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