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4 years ago

How many terms will the given expression have once it is simplified?

Mathematics

2 answers:

8_murik_8 [283]4 years ago

8 0

Answer: C. 3

Step-by-step explanation:

use the distributive property:

8x^2 - 8 + 3x^2 + 6x

then simplify:

11x^2 - 8 + 6x

Sphinxa [80]4 years ago

7 0

Answer:

The answer is C.

I hope this answers the question!

Step-by-step explanation:

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Kate walks 5 miles in 2 hours at a steady pace. how far can she walk in 1 hour and 15 minutes?

jok3333 [9.3K]

Answer:too hard (ywan emoji)

Step-by-step explanation:

4 0

3 years ago

Calculate the volume

Yakvenalex [24]

V = LXHXW
V = 12X20X8 = 1920

7 0

3 years ago

I don’t know how to do that

Alisiya [41]

Answer:

Step-by-step explanation:

Divide 64 by 8 to get 8. this is 1/8 of the books.

3/8 were non fiction, or 24

1/4 (2/8) were picture books, or 16

5/8 were non fiction or picture books, so ’the rest‘ of the chapter books is 3/8.

3/8 were chapter books, or 24.

add the amount of picture books and chapter books since they are the fictional texts.

16+24=40

subtract the amount of non fictional books from the amount of fictional books to get the sum.

40-24=16

8 0

3 years ago

What is the x in 5x+4x+45=180

vlada-n [284]

Finding x for
5x + 4x + 45 = 180

1st step is to combine alike terms
9x + 45 = 180
Now subtract 45 from both sides
9x = 135
Now divide by 9
x = 15

6 0

3 years ago

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays. Assuming the

AysviL [449]

Answer:

1.83% probability there are no car accidents on that stretch on Monday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.

This means that $\mu = 4$

What is the probability there are no car accidents on that stretch on Monday?

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4}*(4)^{0}}{(0)!} = 0.0183$

1.83% probability there are no car accidents on that stretch on Monday

5 0

3 years ago