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3 years ago

Calculate the net force if the forces are parallel 4N 4N

Physics

2 answers:

dusya [7]3 years ago

8 0

Answer:

0 N

Explanation:

iogann1982 [59]3 years ago

5 0

Answer:

The net force is zero Newtons (0 N).

Explanation:

If the forces on one side is 4N and the forces on another side are 4N, the forces cancel out and you have a net force of zero. This means the object is at rest or is moving at a constant rate based on the question.

Hope this helps!

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The area of the tympanic membrane is 100 mm 2 and the area of the oval window is 5 mm 2 . if a sound wave applies 10 n to the ty

Flura [38]

The answer is "0.5N".

According to the question;
P1=P2
so,
F1/A1= F2/A2

P=(F/A)

A1=100mm²

F1= 10N

A2= 5mm²

F2= ?

F2= ((F1 x A2)/A1)
= ((10 x 5) /100)

=50/100

=0.5N

8 0

3 years ago

How many electrons are in the third energy level? 2 8 18 20

Blababa [14]

Answer:

B)8

Explanation:

In the first energy level you can have, at most, 2. Every energy level after that wants to have 8 electrons. Valence electrons I believe.

Hope this helps, have a nice day! (^-^)

6 0

3 years ago

Read 2 more answers

A golf club exerts an average horizontal force of 1005 N in the –x direction on a 453 grams golf ball that is initially at rest

adelina 88 [10]

Answer:

The impulse is 1.89 Ns and final velocity of the golf 4.17 $\frac{m}{s}$

Explanation:

Given:

Average force $F = 1005$ N

Contact time $t = 1.89 \times 10^{-3}$ sec

Mass of golf ball $m = 453 = 0.453$ kg

(a)

Impulse is given by,

$J = Ft$

$J = 1005 \times 1.89 \times 10^{-3}$

$J = 1.89$ Ns

(b)

For finding the final velocity,

$J = \Delta P$

$J = mv$

$1.89 = 0.453 v$

$v = 4.17 \frac{m}{s}$

Therefore, the impulse is 1.89 Ns and final velocity of the golf 4.17 $\frac{m}{s}$

7 0

3 years ago

An 7.9 kg crate is pulled 5.5 m up a 30∘ incline by a rope angled 19 ∘ above the incline. The tension in the rope is 140 N and t

dedylja [7]

Answer:

Wt= 0.73kJ, Wg=0.21kJ Wn= 0J

(B) Wf= 0.096kJ

Explanation:

See attachment below.

5 0

4 years ago

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0

3 years ago