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Orlov [11]
3 years ago
5

A house is 54.0 ft long and 48 ft wide, and has 8.0-ft-high ceilings. What is the volume of the interior of the house in cubic m

eters and cubic centimeters? Answers needs to be in appropriate significant figures.
Physics
1 answer:
pshichka [43]3 years ago
7 0

Explanation:

Length of house, l = 54 ft = 16.45 m

Breadth of house, b = 48 ft = 14.63 m

Height of house, h = 8 ft = 2.43 m

We need to find the volume of the interior of the house. The house is in the form of cuboid. The volume of cuboid is given by :

V=l\times b\times h

V=16.45\ m\times 14.63\ m\times 2.43\ m

V=584.81\ m^3

Since, 1\ m^3=1000000\ cm^3

or the volume of the interior of the house, V=5.84\times 10^8\ cm^3

Hence, this is the required solution.

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gayaneshka [121]

Answer:

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3 years ago
Determine a valid way of finding the wire’s diameter if you know the resistivity of the material, \rho , and can measure the cur
olganol [36]

Answer:

To find the diameter of the wire, when the following are given:

Resistivity of the material (Rho), Current flowing in the conductor, I, Potential difference across the conductor ends, V, and length of the wire/conductor, L.

Using the ohm's law,

Resistance R = (rho*L)/A

R = V/I.

Crossectional area of the wire A = π*square of radius

Radius = sqrt(A/π)

Diameter = Radius/2 = [sqrt(A/π)]

Making A the subject of the formular

A = (rho* L* I)V.

From the result of A, Diameter can be determined using

Diameter = [sqrt(A/π)]/2. π is a constant with the value 22/7

Explanation:

Error and uncertainty can be measured varying the value of the parameters used and calculating different values of the diameters. Compare the values using standard deviation

7 0
3 years ago
A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,
levacccp [35]

Answer:

7.69533\times 10^{-11}\ m^3/s

Explanation:

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l = Length of artery = 1.1\times 10^{-3}\ m

From Poiseuille's equation we have

Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s

The flow rate of blood is 7.69533\times 10^{-11}\ m^3/s

8 0
3 years ago
Find the magnitude of the torque produced by a 4.8 N force applied to a door at a perpendicular distance of 0.43 m from the hing
SVEN [57.7K]

Answer:

2.064 N.m

Explanation:

Torque: This is the force that act on a system, which tends to cause rotation or twisting. The S.I unit of Torque is N.m

Torque is represented mathematically as,

T = F×d........................ Equation 1

Where T = Torque, F = Force, d = perpendicular distance.

Given: F = 4.8 N,  d = 0.43 m.

Substitute into equation 1

T = 4.8×0.43

T = 2.064 N.m

Hence the Torque produced = 2.064 N.m

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Answer:

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