Ask question

Ask question

All categories

riadik2000 [5.3K]

3 years ago

12

GI = 6, HI = 8, DT = 12, what is IE?a.12b.16c.8d.4

1 answer:

harina [27]3 years ago

5 0

Answer:

Option D

Step-by-step explanation:

By the property of intersecting chords,

If two chords are intersecting at a point inside a circle, product of lengths of the line segments on each chord is equal.

DI × EI = HI × GI

12 × EI = 8 × 6

EI = $\frac{48}{12}$

EI = 4

Therefore, Option D is the correct option.

You might be interested in

Which of the choices shown are the lengths of the sides of a right triangle

Triss [41]

D because , 10+ 24 greater than 26
You need take the first and the second number add together must be greater the last one.
10,24,26
10+24 = 34
34>26

5 0

4 years ago

Read 2 more answers

the depth D, in inches, od wsnow in my yard t hours after it started snowing this morning is given by D=1.5t + 4. if the depth o

Blababa [14]

Answer:

8.5 inches

Step-by-step explanation:

First let's find the time t when the depth of the snow is 7 inches.

To do this, we just need to use the value of D = 7 then find the value of t:

$7 = 1.5t + 4$

$1.5t = 3$

$t = 2\ hours$

We want to find the depth of snow one hour from now, so we just need to use the value of t = 3 to calculate D:

$D = 1.5*3 + 4$

$D = 4.5 + 4 = 8.5\ inches$

The depth of snow one hour from now will be 8.5 inches.

7 0

3 years ago

For a school fund-raiser, 10 students sold a total of 90 boxes of cookies. Which of the following can be calculated from this in

allsm [11]

Answer: what of the following

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Name each polynomial by degree and number of terms of -7

denis-greek [22]

Answer: i couldn’t find the answer to this one either

Step-by-step explanation:

4 0

3 years ago

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

3 years ago