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Temka [501]
3 years ago
8

If you invest money, after a certain period of time you’ll get interest. For example, if you invest $2,000 at 5% annual interest

rate, in a year you will have $2,000∙0.05=$100 of annual simple interest in addition to the original amount. If you invest $250.00 at 4% interest rate, what will be the interest?
Mathematics
2 answers:
Rashid [163]3 years ago
7 0

Answer:

The interest at 4 % of $250.00 will be $10

Step-by-step explanation:

If you invest money, after a certain period of time you’ll get interest.

For example, if you invest $2,000 at 5 % annual interest rate, in a year you will have ( $2,000 ) x ( 0.05 ) = $100 of annual simple interest in addition to the original amount.

If you invest $250.00 at 4% interest rate, the interest will be ( $250.00 ) x( 0.04 ) = $10.

Simple interest is based on arithmetic progression and compound interest is based on geometric progression.

Gekata [30.6K]3 years ago
6 0
$250,000 x 0.04 = 10,000 in addition to the original amount
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The function is:
B ( t ) = 4 * e^(0.8 t)
4 * e^(0.8 t) = 400
e^(0.8 t) = 400: 4
e^(0.8 t) = 100   / ln
ln e^(0.8 t) = ln 100  ( and since: ln e = 1 and ln e^x = x * ln e )
0.8 t = 4.6
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Answer:
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3 years ago
Evaluate each expression if f = –4, g = 2, and h = 7.<br><br><br> h – f
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11

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8 0
2 years ago
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130

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2 years ago
If the area of a triangle is 140 inches and the height is 20 inches how wide is the house ?
m_a_m_a [10]

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Step-by-step explanation:

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3 years ago
Write the equation of a parabola whose focus is at (-7, 3) and whose directrix is the line x = -3.
Sav [38]

Check the picture below.

now, let's keep in mind that, the vertex is half-way between the focus point and the directrix, it's a "p" distance from each other.

since this horizontal parabola is opening to the left-hand-side, "p" is negative, notice in the picture, "p" is 2 units, and since it's negative, p = -2.

its vertex is half-way between those two guys, so that puts the vertex at (-5, 3)

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}

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3 years ago
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