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rodikova [14]
3 years ago
14

(2x-5y)^2 (3y+4t)^2 (3-2x)^2 (xy-t)^2 (5x+4x)^2 (9x+7y)^2

Mathematics
1 answer:
garri49 [273]3 years ago
8 0

the first attachment is the problem factored

hope this helps

the other attchments are things that i can relate to

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Harold collected data on the daily high temperature in two cities over a period of one week.
Misha Larkins [42]

Answer:

Correct choices are 1 and 4

Step-by-step explanation:

As per data given we have:

  • Median temperature is 75°F and 88°F
  • And the range from the median is 5° for both cities

This gives us lowest temperatures of:

  • 75° -5° = 70° and 88° - 5°= 83° respectively

And high temperatures are:

  • 75° + 5° = 80° and 88° + 5° = 93°

<u>Answer choices based on above details:</u>

  • Choice 1 - correct
  • Choice 2 - incorrect. Correct answer is 93°
  • Choice 3 - incorrect. Correct answer is 93° - 70° = 23°
  • Choice 4 - correct

3 0
3 years ago
A store is having a 20% off sale. If the
Aleks [24]

Answer:

$64.32

Step-by-step explanation:

What you do is:

$53.60×20% → $53.60×0.2

$53.60×0.2=$10.72

$10.72 is the amount of money taken off because of the sale.

Then what you do is:

$53.60+$10.72=_____

53.60

<u>+10.72</u>

64.32

The original price was $64.32.

Hope this helps! Please mark my answer brainliest!

3 0
3 years ago
Read 2 more answers
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
damaskus [11]

Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

6 0
3 years ago
Solve for w<br> S=2(lw +lh+wh)
Maksim231197 [3]
<span>Solve for w
S=2(lw +lh+wh)

</span>x = \frac{S - 2hl }{2(h + l)}

7 0
3 years ago
» What is the product?<br> 0.9 x 100 =
Zepler [3.9K]
The product of this is 90
4 0
3 years ago
Read 2 more answers
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