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3 years ago

Can you please help me

Mathematics

2 answers:

gulaghasi [49]3 years ago

5 0

Answer:

Step-by-step explanation:

⅝ - 5/9 = 5/72

11111nata11111 [884]3 years ago

3 0

5/72 I think it is :D

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3 years ago

Fast I need to know what 20/22= x/11

sergij07 [2.7K]

Answer:

To Find => The value of x. in the equation below

$20 \div 22 = x \div 11$

Step-by-step explanation:

We will cross Multiply the digits

=>20 \div 22 = x \div 20

=>We'll cross Multiply

$20 \div 22 = x \div 11 \\ = > 22x = 20 \times 11 \\ = > 22x = 220 \\ = > x = 220 \div 22 \\ = > x = 10$

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3 years ago

A scientist is determining how fast a weed grows. Every two days the scientist measures the height of the weed. How tall will th

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Step-by-step explanation:

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3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago