Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
since the ratio of y to x (also written y:x) never changes. The number 6 in the equation yx=6 y x = 6 is called the constant of variation. The equation yx=6 y x = 6 can also be written in the equivalent form, y=6x y = 6 x .
Step-by-step explanation:
The answer is True
Subtract 18 from 72 to get Michelle's current age.
72 - 18 = 54
1. 3h+11
2. -2r
3. g-4
4. 5f+4
5. 15z
