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IgorLugansk [536]
3 years ago
15

Jaxon needs to solve the equation x2 + 12x – 20 = 0 by completing the square. Which pair of steps is the most efficient way to b

egin?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

D. x^2+12x+36=20+36

Step-by-step explanation:

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In the diagram below BD is parallel to XY what is the value of Y
LiRa [457]

Given:

BD is parallel to XY.

One of the angle is 85°

To find:

The value of y.

Solution:

Parallel lines BD and XY cut by a transversal line.

Angle y and 85° are alternate interior angles.

Alternate interior angle theorem:

If two parallel lines are cut by a transversal line, then the pairs of alternate interior angles are congruent.

⇒ y = 85°

The value of y is 85.

4 0
3 years ago
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Solve the equation 6(x-5)=4x+20
Leno4ka [110]

Answer:

25

Step-by-step explanation:

4 0
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Find the slope of (-4,-1) and (-2,-5)
UkoKoshka [18]

Answer:

The slope is -2.

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6 0
2 years ago
T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
Line AB contains points A(-6,1) and B(1,4).
Free_Kalibri [48]

To solve this problem you must apply the proccedure shown below:

1- You have that the equation of the line is:

y=mx+b

Where m is the slope andb is the y-intercept.

2- Based on the information given in the problem, the lines AB andCD are parallel, which means that both have the same slope. Therefore, you can calculate the slope of AB:

m=\frac{y2-y1}{x2-x1}

m=\frac{4-1}{1-(-6)}=\frac{3}{7}

3- Use the coordinates of the point D(7,2) to calculate the y-intercept:

2=\frac{3}{7}(7)+b

4. Solve for b:

b=2-3=-1

5. The equation of the line CD is:

y=\frac{3}{7}x-1

The answer is: y=\frac{3}{7}x-1

6 0
3 years ago
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