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IgorLugansk [536]

3 years ago

15

Jaxon needs to solve the equation x2 + 12x – 20 = 0 by completing the square. Which pair of steps is the most efficient way to b

egin?

1 answer:

Ksenya-84 [330]3 years ago

8 0

Answer:

D. x^2+12x+36=20+36

Step-by-step explanation:

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In the diagram below BD is parallel to XY what is the value of Y

LiRa [457]

Given:

BD is parallel to XY.

One of the angle is 85°

To find:

The value of y.

Solution:

Parallel lines BD and XY cut by a transversal line.

Angle y and 85° are alternate interior angles.

Alternate interior angle theorem:

If two parallel lines are cut by a transversal line, then the pairs of alternate interior angles are congruent.

⇒ y = 85°

The value of y is 85.

4 0

3 years ago

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Solve the equation 6(x-5)=4x+20

Leno4ka [110]

Answer:

25

Step-by-step explanation:

4 0

3 years ago

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Find the slope of (-4,-1) and (-2,-5)

UkoKoshka [18]

Answer:

The slope is -2.

Good Luck

6 0

2 years ago

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

Line AB contains points A(-6,1) and B(1,4).

Free_Kalibri [48]

To solve this problem you must apply the proccedure shown below:

1- You have that the equation of the line is:

$y=mx+b$

Where $m$ is the slope and $b$ is the y-intercept.

2- Based on the information given in the problem, the lines $AB$ and $CD$ are parallel, which means that both have the same slope. Therefore, you can calculate the slope of $AB$ :

$m=\frac{y2-y1}{x2-x1}$

$m=\frac{4-1}{1-(-6)}=\frac{3}{7}$

3- Use the coordinates of the point $D(7,2)$ to calculate the y-intercept:

$2=\frac{3}{7}(7)+b$

4. Solve for $b$ :

$b=2-3=-1$

5. The equation of the line $CD$ is:

$y=\frac{3}{7}x-1$

The answer is: $y=\frac{3}{7}x-1$

6 0

3 years ago