Answer:
Mercury, Venus, Earth, Mars, and Uranus
Step-by-step explanation:
Calculate the escape velocity for each planet, using the equation v = √(2gR).
![\left[\begin{array}{cccc}Planet&R(m)&g(m/s^{2})&v(m/s)\\Mercury&2.43\times10^{6}&3.61&4190\\Venus&6.07\times10^{6}&8.83&10400\\Earth&6.37\times10^{6}&9.80&11200\\Mars&3.38\times10^{6}&3.75&5030\\Jupiter&6.98\times10^{7}&26.0&60200\\Saturn&5.82\times10^{7}&11.2&36100\\Uranus&2.35\times10^{7}&10.5&22200\\Neptune&2.27\times10^{7}&13.3&24600\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7DPlanet%26R%28m%29%26g%28m%2Fs%5E%7B2%7D%29%26v%28m%2Fs%29%5C%5CMercury%262.43%5Ctimes10%5E%7B6%7D%263.61%264190%5C%5CVenus%266.07%5Ctimes10%5E%7B6%7D%268.83%2610400%5C%5CEarth%266.37%5Ctimes10%5E%7B6%7D%269.80%2611200%5C%5CMars%263.38%5Ctimes10%5E%7B6%7D%263.75%265030%5C%5CJupiter%266.98%5Ctimes10%5E%7B7%7D%2626.0%2660200%5C%5CSaturn%265.82%5Ctimes10%5E%7B7%7D%2611.2%2636100%5C%5CUranus%262.35%5Ctimes10%5E%7B7%7D%2610.5%2622200%5C%5CNeptune%262.27%5Ctimes10%5E%7B7%7D%2613.3%2624600%5Cend%7Barray%7D%5Cright%5D)
The rocket's maximum velocity is double the Earth's escape velocity, or 22,400 m/s. So the planets the rocket can escape from are Mercury, Venus, Earth, Mars, and Uranus.
Answer: The value of P(E∪F) = 0.64.
Step-by-step explanation:
Since we have given that
P(E) = 0.38
P(F) = 0.38
P(E∩F) = 0.12
So, we need to find the P(E∪F).
As we know the formula for the sets.
Hence,the value of P(E∪F) = 0.64.
Answer:
y= x less than 1.5 +4.25
Step-by-step explanation:
Answer:
D a reflection over a line through point P followed by a dilation centered at point P
Multiply the denominators together and the numerators together and you have your answer
