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3 years ago

Simplify.

Mathematics

1 answer:

atroni [7]3 years ago

6 0

Answer:

lol hope you do wellฅ^•ﻌ•^ฅ

Step-by-step explanation:

what what level is it

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2(3x-7)=34 please help

IrinaK [193]

Answer:

x=8

Step-by-step explanation:

2*3x=6x

2*-7=-14

6x-14=34

6x+14=34+14

6x=48

6x/48

x=8

3 0

2 years ago

If sin= 7/25 what are the other primary trig ratios?

statuscvo [17]

Answer:

cos=24/25

tan=7/24

Step-by-step explanation:

sin=opposite/hypotenuse

therefore 7 is the opposite and 25 is the hypotenuse.

using pythagorean theorem we can find the adjacent. i.e hypotenuse squared= sum of adjacent squared and opposite squared.

h^2= a^2+ O^2

25 squared - 7 squared= 576

which is equal to 24 squared.

therefore adjacent=24

cos=adjacent/hypotenuse

cos=24/25

tan=opposite/adjacent

tan=7/24.

8 0

2 years ago

Read 2 more answers

How can you turn 4512 into a mixed number?

arlik [135]

Yes, you would get 3 3/4.<span><span>
</span></span>

4 0

3 years ago

Read 2 more answers

12X12= ___+144-88=___

nalin [4]

12x12=144+144-88=200 good luck!

4 0

3 years ago

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Please for the love of god anwser my question lay correctly I really need your help :( I will give 25 points :)! This is geometr

tangare [24]

Answer:

$\displaystyle \rm A_{ \text{c - pentagon}} =41$

$\rm \displaystyle P _{ \rm c - pentagon} = 20+ 4 \sqrt{2}$

Step-by-step explanation:

we have a square and a triangle

we want to figure out the area and the perimeter of the pentagon

to figure out the area of the pentagon we can use the given formula:

$\displaystyle \rm A_{ \text{c - pentagon}} = A_{ \text{squre}} - A_{ \text{triangle}}$

let's figure out $A_{\rm square}$ :

since the given shape is a square Every angle of its 90° Thus the triangle is a right angle triangle

therefore the height is 4

$\displaystyle A _{ \rm triangle} = \frac{1}{2} \times b \times h$

substitute h and b

$\displaystyle A _{ \rm triangle} = \frac{1}{2} \times 4 \times 4$

reduce fraction:

$\displaystyle A _{ \rm triangle} = 2 \times 4$

simplify multiplication:

$\displaystyle A _{ \rm triangle} = 8$

likewise square

$\displaystyle A _{ \rm squre} = {s}^{2}$

substitute s:

$\displaystyle A _{ \rm squre} = {7}^{2}$

simplify square

$\displaystyle A _{ \rm squre} = 49$

hence,

$\displaystyle \rm A_{ \text{c - pentagon}} =49- 8$

$\displaystyle \rm A_{ \text{c - pentagon}} =41$

to figure out perimeter

let's figure out hypotenuse first

$\displaystyle h = \sqrt{ {4}^{2} + {4}^{2} }$

$\displaystyle h = \sqrt{ 16 + 16}$

$\displaystyle h = 4 \sqrt{2}$

therefore,

$\rm \displaystyle P _{ \rm c - pentagon} = 3 + 3 + 4 \sqrt{2} + 7 + 7$

$\rm \displaystyle P _{ \rm c - pentagon} = 6 + 4 \sqrt{2} + 14$

$\rm \displaystyle P _{ \rm c - pentagon} = 20+ 4 \sqrt{2}$

5 0

3 years ago