B)all solutions are mixtures
Answer:
155 A
Explanation:
Given data
- Transported charge (Q): 93.0 Coulomb
- Elapsed time (t): 601 ms = 0.601 seconds
We can determine the magnitude of the electric current (I) using the following expression.
I = Q / t
I = 93.0 C / 0.601 s
I = 155 C/s
I = 155 A
The magnitude of the electric current is 155 Ampere.
Answer:
ΔH = 41.7 kj
Given data:
Mass of ethanol = 50 g
Heat required to vaporize = ?
Boiling point of ethanol = 78.3°C
Molar heat of vaporization = 38.6 kj/mol
Solution:
First of all we will calculate the number of moles.
Number of moles = mass / molar mass
Number of moles = 50 g/ 46.07 g/mol
Number of moles = 1.08 mol
ΔH = 38.6 kj/mol ×1.08 mol
ΔH = 41.7 kj
Explanation:
The units of light energy emitted by blackbody radiation is originally called as quanta. Black body radiation is a type of radiation within a boy in thermodynamic equilibrium. This is a theoretical body. In 1900, Planck proposed that light and other electromagnetic waves were emitted in discrete packets of energy which were called "quanta". This was the original unit used.
Answer : The chemical formula for the compound is, 
Explanation :
When the element 'M' react with the 
to give .
The balanced chemical reaction is,
In this reaction, 'M' is in mono-atomic form and is in diatomic form.
By the stoichiometry,
2 moles 'M' react with the 1 mole of to give 2 moles of .
Therefore, the chemical formula of the compound is,
