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Maurinko [17]
3 years ago
15

A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 8.4 g of water (with an

initial temperature of 20 °C) in a calorimeter. The final temperature of the system is 52.1°C. The specific heat of water is 4.184 J/g*⁰C. What is the specific heat of the metal?
3.433
0.171
0.343
1.717
Chemistry
1 answer:
Elden [556K]3 years ago
8 0

Ans1.717

Explanation:

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Two substances A and B, initially at different temperatures, are thermally isolated from their surroundings and allowed to come
Elden [556K]

Answer:

B

Explanation:

For solving this we need a heat balance

Q_{a} = Q_{b}\\m_{a}*C_{a}*\Delta T_{a} = m_{b}*C_{b}*\Delta T_{b}

By changing the corresponding relations, we have

m_{a}*C_{a}*\Delta T_{a} = \frac{1}{2}m_{a}*4C_{a}*\Delta T_{b} \\\\\\

By cancelling similar factor, we obtain

\Delta T_{a} = 2 \Delta T_{b}\\\frac{\Delta T_{a}}{\Delta T_{b}} = 2\\

Which means that the change of temperature in A is twice the change of B

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Fabric is made of ___​
GuDViN [60]

Answer:

Fabric is made of cotton.

Explanation:

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6 0
3 years ago
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The heating element of a hair dryer dissipates 1500 w when connected to a 180 v outlet. part a what is its resistance?
Sophie [7]

The resistance of the heating element is 21.61 Ω

Given

The power dissipated = 1500 W

Voltage = 180 V

We know that

Power = Voltage * Current

⇒ Power / Voltage = Current

⇒ 1500 W/180 V = Current

⇒ 8.33 A = Current

In order to calculate the resistance of the heating element. We Have to apply the formula

Power = (Current)^2 * Resistance

⇒ Resistance = Power / (Current)^2

⇒ Resistance = 1500 W/ (8.33) ^2

⇒ Resistance = 21.61 Ω

Hence the resistance of the heating element is 21.61 Ω

Learn more about resistance here: -

“ brainly.com/question/17330679  “

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Which of the following is the best definition of convection?
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Answer:

Alright, the first thing we have to do is to balance the chemical equation

2Na3N -----> 6Na + 1N2

We have 60g of Na3N, we convert them into moles by dividing the mass of the compound by the molar mass.

Molar mass of Na3N = (22.98 x 3) + (14) = 82.94g/mol

  <u>60</u>          =  0.72341451651 moles of Na3N

82.94

Now because we did the balanced equation, we know the mole to mole ratio of Na3N to N2 would be 2:1, so in order to get the moles of N2 you have to divide the moles of Na3N by 2

0.72341451651 moles/2 = 0.361707258 moles of N2

Now that we have the moles of N2, we just have to determine the mass of it in grams. In order to do that, just multiply the moles by the molar mass of N2 (28g/mol)

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<u>Therefore the decomposition of 60g of Na3N would result in 10.13g of N2 (nitrogen gas)</u>

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