Ask question

Ask question

All categories

2 years ago

14

For the reaction H2O(g) + Cl2O(g) → 2HCIO(9), you know S rxn and Sosys and S° of HCIO(g) and of H2O(g). Write an expression that

can be used to determine Cl2O(g)

1 answer:

Liono4ka [1.6K]2 years ago

3 0

The expression that can be used to determine Cl2O(g) is ;

$S_{cl_{2}o(g) } ^{o} = 2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) }^{o} - \beta S_{rxn} ^{o}$

<h3>Determine an expression that can be used to determine Cl2O(g)</h3>

The general expression for ΔS°rxn of a chemical reaction

ΔS°rxn = ∑mS°products - ∑nS°reactants

where ; m and n = stoichiometry coefficients

Considering the given reaction : H₂O(g) + Cl₂O(g) → 2HCIO (g)

$\beta$ S°rxn = $2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) } ^{o} - S_{Cl_{2}O } ^{o}$ ------- ( 2 )

Rearranging the equation above

$S_{cl_{2}o(g) } ^{o} = 2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) }^{o} - \beta S_{rxn} ^{o}$

Hence we can conclude that The expression that can be used to determine Cl2O(g) is ;

$S_{cl_{2}o(g) } ^{o} = 2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) }^{o} - \beta S_{rxn} ^{o}$

Learn more about stoichiometry : brainly.com/question/16060223

You might be interested in

When the solid and liquid phases are present together simultaneously which phase solid liquid contains the greater amount of ene

enot [183]

Liquid because it is changing to that <span />

3 0

4 years ago

How many moles are present in

olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of $N_{2}$ molecule.

(b) There are 2 moles present in $12.044 \times 10^{23}$ particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of $N_{2}$ is 28 g/mol so its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol$

So, there are 0.428 moles present in 12 g of $N_{2}$ molecule.

(b). According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{23}$ atoms.

Therefore, moles present in $12.044 \times 10^{23}$ particles are calculated as follows.

$Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol$

So, there are 2 moles present in $12.044 \times 10^{23}$ particles of oxygen.

4 0

3 years ago

a phase change from B to A will represent a loss of energy. what is the term to describe this transition if B is the liquid phas

Reptile [31]

Answer:

freezing

Explanation:

The process in which a liquid changes to a solid is called freezing or solidification. Energy is taken away during freezing.

5 0

3 years ago

Through photosynthesis a simple sugar is produced. where do the carbon atoms come from to produce this sugar molecule? carbonyl

miskamm [114]

The carbon comes from carbon dioxide

8 0

4 years ago

Read 2 more answers

H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.06×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.18×10−19, what is the equilibrium constant Kfinal for

serg [7]

Answer:

Therefore the equilibrium constant $K_{final}$ is 9.35× 10²⁵

Explanation:

Equilibrium constant:

Equilibrium constant is used to find out the ratio of the concentration of the product to that of reactant.

xA+yB→zC

The equilibrium constant K,

$k=\frac{[C]^z}{[A]^x[B]^y}$

Here [A] is equilibrium concentration of A

[B] is equilibrium concentration of B

[C] is equilibrium concentration of C.

1. $H_2S(aq)\rightleftharpoons HS^-(aq)+H^+(aq)$ $K_1= 9.06 \times 10^{-8}$

$K_1=\frac{[HS^-][H^+]}{[H_2S]}$

2. $HS^-(aq)\rightleftharpoons S^{2-}(aq)+H^+(aq)$ $K_2= 1.18 \times 10^{-19}$

$K_2=\frac{[S^{2-}][H^+]}{[HS^-]}$

3.

$S^{2-}(aq)+2H^+(aq)\rightleftharpoons H_2S(aq)$

$K_3=\frac{[H_2S]}{[S^{2-}][H^+]^2}$

Therefore,

$k_1k_2=\frac{[HS^-][H^+]}{[H_2S]}\frac{[S^{2-}][H^+]}{[HS^-]}$

$\Rightarrow k_1k_2=\frac{[S^{2-}][H^+]^2}{[H_2S]}$

$\Rightarrow k_1k_2=\frac{1}{K_3}$

$\Rightarrow K_3=\frac{1}{K_1K_2}$

$\Rightarrow K_3=\frac{1}{9.06\times 10^{-8}\times 1.18\times 10^{-19}}$

⇒K₃=9.35× 10²⁵

$K_3=K_{final}$

Therefore the equilibrium constant $K_{final}$ is 9.35× 10²⁵

3 0

3 years ago