Answer:
The correct answer is B
Explanation:
There they were changed into a frost giant whose name was Ymir (e'mir). "There" provides the transition from the previous sentence and refers to the place where the transformation occurred.
Area of circle is 76.44 square units.
We are given that
Base of one sector = b = 1.95 units
Height of sector = h = 4.9 units
Total number of sectors = 16
Area of one sector is equal to area of triangle (approximately)
Area of sector = ![\frac{1}{2} \times b \times h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20b%20%5Ctimes%20h)
Using the formula
Area of one sector= ![\frac{1}{2} \times (1.95) \times (4.9)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%281.95%29%20%5Ctimes%20%284.9%29)
= 4.7775 square units
Area of circle A = 16 × Area of sector
Area of circle A = 16 × 4.7775
= 76.44 square units
Hence, Area of circle is 76.44 square units.
Option D is true.
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Answer:
Oil paint was now the medium of choice, perspective had been mastered as had the skills of facial expression and depth of color. Renaissance art, painting, sculpture, architecture, music, and literature produced during the 14th, 15th, and 16th centuries in Europe under the combined influences of an increased awareness of nature, a revival of classical learning, and a more individualistic view of man. Elements of Renaissance painting are
Linear perspective.
Landscape.
Light.
Anatomy.
Realism.
Figure composition.
Altarpieces.
Fresco cycles.
Can you translate in English
Using implicit differentiation, and considering that the inflation rate is of 200 cubic feet per minute and the radius is of 5 feet, it is found that:
- The radius is increasing at a rate of 0.6366 feet per minute.
- The surface area is changing at a rate of 80 feet squared per minute.
The volume of an <u>sphere of radius r</u> is given by:
![V = \frac{4\pi r^3}{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D)
Applying <em>implicit differentiation</em>, the rate of change is given by:
![\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%204%5Cpi%20r%5E2%5Cfrac%7Bdr%7D%7Bdt%7D)
For this problem:
- Inflation rate of 200 cubic feet per minute, hence
![\frac{dV}{dt} = 200](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20200)
- Radius is of 5 feet, hence
![r = 5](https://tex.z-dn.net/?f=r%20%3D%205)
Then:
![\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%204%5Cpi%20r%5E2%5Cfrac%7Bdr%7D%7Bdt%7D)
![200 = 4\pi (5)^2\frac{dr}{dt}](https://tex.z-dn.net/?f=200%20%3D%204%5Cpi%20%285%29%5E2%5Cfrac%7Bdr%7D%7Bdt%7D)
![\frac{dr}{dt} = \frac{200}{100\pi}](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D%20%3D%20%5Cfrac%7B200%7D%7B100%5Cpi%7D)
![\frac{dr}{dt} = 0.6366](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D%20%3D%200.6366)
The radius is increasing at a rate of 0.6366 feet per minute.
The surface area is:
![S = 4\pi r^2](https://tex.z-dn.net/?f=S%20%3D%204%5Cpi%20r%5E2)
Hence, the <em>rate of change</em> is:
![\frac{dS}{dt} = 8\pi r\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdS%7D%7Bdt%7D%20%3D%208%5Cpi%20r%5Cfrac%7Bdr%7D%7Bdt%7D)
Hence:
![\frac{dS}{dt} = 8\pi (5)(0.6366) = 80](https://tex.z-dn.net/?f=%5Cfrac%7BdS%7D%7Bdt%7D%20%3D%208%5Cpi%20%285%29%280.6366%29%20%3D%2080)
The surface area is changing at a rate of 80 feet squared per minute.
A similar problem is given at brainly.com/question/9543179